Answer:
a. yes
b. no
c. yes
d. yes
Step-by-step explanation:
For a, 27 + 38 can be broken apart. 27 is broken up by adding smaller numbers (20 + 7 = 27) and the same is done with 38 (30 + 8 = 38), so A and C shows a way to add 27 and 38. In C, the numbers are just put into a different order. B is not a way to add 27 and 38, because the sum is different.
27 + 38 = 65, however 20 + 70 + 38 = 128. The addition problem for D is a way to solve for 27 + 38, because it is broken up differently than A and C. They instead added the 20 and 30 together first, then split up 15 (from 8+7) into 10 and 5. So D is a way to solve, because it gets the same answer as 27 and 38 :D
Answer:
x =√[y²+(27)²] = √[ z² - 3² +(27)²]
Step-by-step explanation:
step 1) x=√[y²+(27)²]
step 2)
We find y
z²=y²+3² → y² = z² - 3²
step 3) x = √[ z² - 3² +(27)²]
Answer:
B and D
Step-by-step explanation:
X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1
Answer:
Step-by-step explanation:
zeroes are when you plug in that x value and get y=0
therefore if you set x = that number and solve for 0 you get a "function"
multiplying these together will yield the complete 3rd degree polynomial
x = 1
x-1=0
x=7
x-7=0
x=-4
x+4=0
If needed you could expand but I'm too lazy
