Answer:
Explanation:
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In this case, considering that the compound is 48% oxygen, we infer it is 52% chromium, therefore, by using their atomic masses we compute the moles by assuming those percentages as masses:
Next, by dividing by the smallest moles, we find the subscripts in the empirical formula:
Which are also expressed in the smallest whole numbers, therefore the empirical formula is:
Which corresponds to the chromic oxide or chromium (IV) oxide.
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The theoretical yield of HCl produced is 56.06 grams of HCl
<u><em>calculation</em></u>
BCl₃(g) +3 H₂O(l) → H₃BO₃(s) + 3 HCl(g)
Step 1: find the moles of each reactant
moles = mass÷molar mass
moles of BCl₃ = 60.0 g÷117.16 g/mol =0.512 moles
moles of H2O = 37.5 g ÷18 g/ mol = 2.083 moles
Step 2: use the moles ratio to determine the limiting reagent
from the equation above BCl₃ :HCl is 1:3 therefore the moles of HCl = 0.512 moles x 3/1 =1.536 moles
H2O :HCl is 3:3 = 1:1 therefore the moles of HCl is also 2.083 moles
Bcl₃ is the limiting reagent since it produces less amount of HCl therefore the moles HCl is 1.536 moles
Step 3 ; find the theoretical yield
The theoretical yield = moles x molar mass
from periodic table the molar mass of HCl = 1+ 35.5= 36.5 g/mol
Theoretical yield= 1.536 moles x 36.5 g/mol =56.06 g of Hcl
The picture illustrates copper because of the color and texture. You can also tell it’s a metal, which is what copper is and that’s why it’s an element.