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Natalka [10]
4 years ago
7

E=mc2 sun is losing 4.3 billion kg mass each second ? can you let me know why ?

Physics
1 answer:
Vanyuwa [196]4 years ago
7 0
Yes I can. You've come to the right place. The reason is because that's where the sun's energy comes from. The sun converts that much mass into energy every second. Then the energy leaves the Sun and shines out into space. A tiny tiny tiny tiny tiny bit of it hits the Earth and it sustains life on Earth.
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What do tripped circuit breakers and blown fuses indicate.
vladimir2022 [97]

Answer:

When a circuit breaker regularly trips or a fuse repeatedly blows, it is a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits. Or, it may indicate that your house has too few circuits and is in need of a service upgrade.

7 0
2 years ago
Question 1 of 25
finlep [7]

Answer:

<em>2.753*10^-11N</em>

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

<em>Hence the gravitational force between the asteroid is 2.753*10^-11N</em>

<em></em>

6 0
3 years ago
A force 80N accelerates a 5kg body .Find the acceleration if the coefficient of friction is 0.44
allochka39001 [22]

Answer:

Explanation:

20n

4 0
3 years ago
A hot ball of gas in outer space that creates its own energy is called a _____.
Fynjy0 [20]
It's called a star when it creates its own energy
3 0
3 years ago
It requires 49 J of work to stretch an ideal very light spring from a length of 1.4 m to a length of 2.9 m. What is the value of
nadya68 [22]

Answer:

44 N/m

Explanation:

The extension, e, of the spring = 2.9 m - 1.4 m = 1.5 m

The work needed to stretch a spring by <em>e</em> is given by

W = \frac{1}{2} ke^2

where <em>k</em> is spring constant.

k = \dfrac{2W}{e^2}

Using the appropriate values,

k = \dfrac{2\times 49\text{ J}}{1.5^2\text{ m}^2} = 43.55\ldots\text{ N/m} \approx 44\text{ N/m}

3 0
3 years ago
Read 2 more answers
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