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Natalka [10]
3 years ago
7

E=mc2 sun is losing 4.3 billion kg mass each second ? can you let me know why ?

Physics
1 answer:
Vanyuwa [196]3 years ago
7 0
Yes I can. You've come to the right place. The reason is because that's where the sun's energy comes from. The sun converts that much mass into energy every second. Then the energy leaves the Sun and shines out into space. A tiny tiny tiny tiny tiny bit of it hits the Earth and it sustains life on Earth.
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What shape is the Milky way galaxy
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It appears to be a <span>spiral shape. </span>
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Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
frosja888 [35]

Answer:

C) True. S increases with time, v₁ = gt and v₂ = g (t-t₀)  we see that for the same t v₁> v₂

Explanation:

You have several statements and we must select which ones are correct. The best way to do this is to raise the problem.

Let's use the vertical launch equation. The positive sign because they indicate that the felt downward is taken as an opponent.

Stone 1

    y₁ = v₀₁ t + ½ g t²

    y₁ = 0 + ½ g t²

Rock2

It comes out a little later, let's say a second later, we can use the same stopwatch

     t ’= (t-t₀)

    y₂ = v₀₂ t ’+ ½ g t’²

    y₂ = 0 + ½ g (t-t₀)²

    y₂ = + ½ g (t-t₀)²

Let's calculate the distance between the two rocks, it should be clear that this equation is valid only for t> = to

    S = y₁ -y₂

    S = ½ g t²– ½ g (t-t₀)²

    S = ½ g [t² - (t²- 2 t to + to²)]  

    S = ½ g (2 t t₀ - t₀²)

    S = ½ g t₀ (2 t -t₀)

This is the separation of the two bodies as time passes, the amount outside the Parentheses is constant.

For t <to.  The rock y has not left and the distance increases

For t> = to.  the ratio (2t/to-1)> 1 therefore the distance increases as time

passes

Now we can analyze the different statements

A) false. The difference in height increases over time

B) False S increases

C) Certain s increases with time, v₁ = gt and V₂ = g (t-t₀) we see that for the same t   v₁> v₂

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3 years ago
If the faster stone takes 12.0 s to return to the ground, how long will it take the slower stone to return?
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A bicyclist moves at a constant speed of 6 m/s. How long it will take for the point bicyclist to move 36 m?​
Rudik [331]

Answer:

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3 years ago
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Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
yaroslaw [1]

Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

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tells us that

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           0 = 8 m_b v_a + m_b v_b

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indicate that the transfer is complete, therefore the kinematic energy is conserved

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final point. After separating the body

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           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

           

we substitute equation 1

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           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

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3 years ago
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