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torisob [31]
3 years ago
8

A hot ball of gas in outer space that creates its own energy is called a _____.

Physics
1 answer:
Fynjy0 [20]3 years ago
3 0
It's called a star when it creates its own energy
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Calculate the wavelengths of the first five emission lines of the Balmer series for hydrogen
In-s [12.5K]

Answer:

Explanation:

The Balmer series in a hydrogen atom relates the possible electron transitions down to the n = 2 position to the wavelength of the emission that scientists observe. In quantum physics, when electrons transition between different energy levels around the atom (described by the principal quantum number, n) they either release or absorb a photon. The Balmer series describes the transitions from higher energy levels to the second energy level and the wavelengths of the emitted photons. You can calculate this using the Rydberg formula.

5 0
3 years ago
Which of the following is one part of a chemical formula?
a_sh-v [17]

Answer:A

Explanation: number that shows the total atomic mass of the substance

5 0
4 years ago
Read 2 more answers
An element’s atomic number is 35. how many portions would an atom this element have
kotykmax [81]

35 protons are present in an element whose atomic number is 35.

<u>Explanation: </u>

In an atom of an element, the number of protons = atomic number

Number of protons = number of electrons

Mass Number = number of protons + number of neutrons

Hence, an atom with atomic number 35 will have 35 protons.

4 0
4 years ago
If gas si supplied by a pipe which pass through a mesuarer to your house, Which case would you pay more for it?
Triss [41]
A.) When its cold .
4 0
3 years ago
A 6.50-m-long iron wire is 1.50 mm in diameter and carries a uniform current density of 4.07 MA/m^2. Find the voltage between th
Sauron [17]

Answer:

V = 0.45 Volts

Explanation:

First we need to find the total current passing through the wire. That can be given by:

Total Current = I = (Current Density)(Surface Area of Wire)

I = (Current Density)(2πrL)

where,

r = radius = 1.5/2 mm = 0.75 mm = 0.75 x 10⁻³ m

L = Length of Wire = 6.5 m

Therefore,

I = (4.07 x 10⁻³ A/m²)[2π(0.75 x 10⁻³ m)(6.5 m)]

I = 1.25 x 10⁻⁴ A

Now, we need to find resistance of wire:

R = ρL/A

where,

ρ = resistivity of iron = 9.71 x 10⁻⁸ Ωm

A = Cross-sectional Area = πr² = π(0.75 x 10⁻³ m)² = 1.77 x 10⁻⁶ m²

Therefore,

R = (9.71 x 10⁻⁸ Ωm)(6.5 m)/(1.77 x 10⁻⁶ m²)

R = 0.36 Ω

From Ohm's Law:

Voltage = V = IR

V = (1.25 x 10⁻⁴ A)(0.36 Ω)

<u>V = 0.45 Volts</u>

4 0
3 years ago
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