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2 years ago

Question 1 of 25

Physics

1 answer:

finlep [7]2 years ago

6 0

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

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A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.

fenix001 [56]

Question

What is the length of the pipe?

Answer:

(a) 0.52m

(b) f2=640 Hz and f3=960 Hz

Explanation:

For an open pipe, the velocity is given by

$v=\frac {2Lf}{n}$

Making L the subject then

$L=\frac {nV}{2f}$

Where f is the frequency, L is the length, n is harmonic number, v is velocity

Substituting 1 for n, 320 Hz for f and 331 m/s for v then

$L=\frac {1*331}{2*320}=0.5171875\approx 0.52m$

(b)

The next two harmonics is given by

f2=2fi

f3=3fi

f2=3*320=640 Hz

f3=3*320=960 Hz

Alternatively, $f2=2\times \frac {v}{2L}$ and $f3=3\times \frac {v}{2L}$

$f2=2\times \frac {331}{2*0.52}=636.5 Hz\\f3=3\times \frac {331}{2*0.52}=954.8 Hz$

(c)

When v=367 m/s then

$f1= \frac {v}{2L}\\f1= \frac {367}{2*0.52}=352.9 Hz$

5 0

3 years ago

Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed o

kobusy [5.1K]

Answer:

$\Delta \lambda=14.3\ nm$

Explanation:

It is given that,

The number of lines per unit length, N = 900 slits per cm

Distance between the formed pattern and the grating, l = 2.3 m

n the first-order spectrum, maxima for two different wavelengths are separated on the screen by 2.98 mm, $\Delta Y=2.98\ mm = 0.00298\ m$

Let d is the slit width of the grating,

$d=\dfrac{1}{N}$

$d=\dfrac{1}{900\ cm}$

$d=1.11\times 10^{-5}\ m$

For the first wavelength, the position of maxima is given by :

$y_1=\dfrac{L\lambda_1}{d}$

For the other wavelength, the position of maxima is given by :

$y_2=\dfrac{L\lambda_2}{d}$

So,

$\Delta \lambda=\dfrac{\Delta y d}{l}$

$\Delta \lambda=\dfrac{0.00298\times 1.11\times 10^{-5}}{2.3}$

$\Delta \lambda=1.43\times 10^{-8}\ m$

$\Delta \lambda=14.3\ nm$

So, the difference between these wavelengths is 14.3 nm. Hence, this is the required solution.

3 0

2 years ago

How many times is larger than a centigram is a dekagram

S_A_V [24]

A decagram is 1000 times bigger than a centigram

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3 years ago

Easy quiz easy points 7

Darya [45]

The answer is 2: hush

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3 years ago

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Determine the Specific Heat Capacity (Cs) of the liquid. Where: Mass of liquid (M₂) = 0.0012Kg, Initial temperature (₁)=23°C, Fi

alexandr1967 [171]

The Specific Heat Capacity of the liquid is 43.846 KJ/(Kg K).

It is given that Mass of liquid (M) = 0.0012Kg, Initial temperature (T1) = 23°C, Final temperature (T2) = 62°C, Voltage (V) = 8v, Current (I) = 0.95A, Time (t) = 270s

The quantity of heat that must be applied to an object in order to cause a unit change in temperature is known as the heat capacity or thermal capacity of that object.
We know that heat capacity for a substance is :
H = m*C*ΔT - equation (1)

When a conductor is subjected to current flow, the conductor's free electrons are set in motion and collide with one another. Moving electrons experience kinetic energy loss and partial thermal energy conversion as a result of the collision. This impact of current is referred to as its heating effect.
Due to electric current, heat energy is :
H = Power * Time
H = Current * Voltage * Time
H = I*V*t - equation (2)

Using equation (1) and (2),
m*C*ΔT = I*V*t
Substituting the values for m, ΔT, I, V and t.
0.0012Kg * C * (62 - 23)K = 0.95A * 8v * 270s
Solving for C, we get C = 43.846 KJ/(Kg K)

To learn more about Specific Heat Capacity visit :

brainly.com/question/1747943

#SPJ9

3 0

1 year ago