Answer:
43.56 N/m
Explanation:
From Hook's Law,
The Energy stored in a spring is given as
E = 1/2ke².......................... Equation 1
Where E = Energy stored in the spring, k = spring constant of the spring, e =. extension
make k the subject of the equation
k = 2E/e²....................... Equation 2
Given: E = 49 J, e = 2.9-1.4 = 1.5 m.
Substitute into equation 2
k = 2(49)/1.5²
k = 98/2.25
k = 43.56 N/m.
Hence the spring constant of the spring = 43.56 N/m