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Svetradugi [14.3K]
4 years ago
11

LOL SOMEONE DO THIS FOR ME!!!

Physics
1 answer:
olganol [36]4 years ago
4 0
Build a filter.
Dig water from the ground
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Answer True or Flase1-Electric potential due to a uniform E field doesn’t change with location.2-The equipotential surfaces asso
TEA [102]

Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}

There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.

3 0
3 years ago
During a neap tide, which phase could the moon be in? select all that apply
snow_lady [41]
Hello,

Here is your answer:

The proper answer to this question is option B "<span>third quarter".

Here is how:

Neap tides are caused when the moon is three thirds full which causes the current to up rise therefore making a neap tide.

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!

</span>
4 0
3 years ago
Read 2 more answers
What is the change in potential energy with respect to the ground of a 0.55 g son of a leech (a very effective fly for steelhead
IceJOKER [234]

Answer:

We will use Potential Energy Formula

Potential Energy = mass × gravitation × height

PE = 0,55 × 10 × 4

PE = 22 J (A)

5 0
3 years ago
Given that the internal energy of water at 28 bar pressure is 988 kJ kg–1 and that the specific volume of water at this pressure
klasskru [66]

Answer:

1184 kJ/kg

Explanation:

Given:

water pressure P= 28 bar

internal energy U= 988 kJ/kg

specific volume of water v= 0.121×10^-2 m^3/kg

Now from steam table at 28 bar pressure we can write

U= U_{f}= 987.6 kJ/Kg

v_{f}=v=1.210\times 10^{-3}m^{^{3}}/kg

therefore at saturated liquid we have specific enthalpy at 55 bar pressure.

that the specific enthalpy h =  h at 50 bar +(55-50)/(60-50)*( h at 50 bar - h at 60 bar)

h= 1154.5 + \frac{5}{10}\times(1213-1154)

h= 1184 kJ/kg

5 0
3 years ago
The saturnian moon io probably collided with
LUCKY_DIMON [66]
The Voyager and Pioneer flybys of the 1970s and 1980s provided rough sketches of Saturn’s moons. But during its many years in Saturn orbit, Cassini discovered previously unknown moons, solved mysteries about known ones, studied their interactions with the rings and revealed how sharply different the moons are from one another.
8 0
3 years ago
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