The work done by friction to move the sled is - 1,323 J.
<h3>
What is Coefficient of friction?</h3>
- The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them.
- Typically, it is represented by the Greek letter µ. In terms of math, is equal to F/N, where F stands for frictional force and N for normal force.
- The coefficient of friction has no dimensions because both F and N are measured in units of force (such as newtons or pounds). For both static and kinetic friction, the coefficient of friction has a range of values.
- When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. The frictional force opposes an object's motion in kinetic friction.
Solution:
Given that
Coefficient of friction (µ) = 0.10
Mass (m) = 90kg
distance covered (d) = 30m
We use the formula:
friction work = -µmgdcos∅
friction work = -0.100 × 90 kg × 9.8 m/s² × 30 m × cos 60°
friction work = - 1,323 J
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Answer:
Explanation:
Direction of velocity of electromagnetic wave is given by the formula
E = E j ( vector form )
B = - Bi ( vector form )
Direction of velocity = direction of vector E X B
= E X B
= E j x -Bi
= - EB -k
v = EBk
So the direction of velocity will be along z direction.
Answer: aluminum chlorine and iron(lll) oxide
Explanation:
To be honest, there's no sure way to answer that, because you haven't defined your terms and we can't be sure of what j or s might be.
Tell you what I'll do:. I'll assume definitions for j and s, and then I'll answer the question that I invented.
Assume that j stands for Joule, the unit of energy. And assume that s stands for 'second', the unit of time.
Then j/s is the rate of transferring energy or doing work.
Its unit is the Watt, equivalent to 1 Joule per second.
In your system of notation, it would be 'w' .
The whole point of this problem is to check how well you understand
the definitions of a few important quantities, like velocity, speed, distance,
displacement etc.
Before we begin, I just want to mention that 'MPG' is not a unit of either
velocity or speed, but I think I know what you mean.
-- For some reason, Ms. Eaddy rode 100 miles north on the train, then
stayed aboard while the train turned around and took her 150 miles south.
The total distance she rode was (100 + 150) = 250 miles. But she ended up
50 miles south of where she began.
-- Displacement for the whole trip = distance and direction from the start point
to the finish point.
Displacement = 50 miles south
-- Average velocity = (displacement) / (time)
50 miles south / 3.5 hours = <u>14.29 miles per hour south</u>
