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Hitman42 [59]
3 years ago
12

A rock falls off a 15 meter cliff. How fast is the rock traveling vertically two seconds later?

Physics
1 answer:
oksian1 [2.3K]3 years ago
8 0
The acceleration of gravity on Earth is 9.8 m/s².  That means that
an object falling under the influence of gravity will move 9.8 m/s
faster than it was moving a second earlier.

Falling from rest, it will be moving 9.8 m/s after the first second,
and 19.6 m/s after the 2nd second.

The height from which it fell doesn't matter.
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Why is it important to have a strong core (mid section)?
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Answer:

Your core stabilizes your body, allowing you to move in any direction as well as having proper balance. It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability.

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3 years ago
An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
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7 0
3 years ago
A 80 kg skier grips a moving rope that is powered by an engine and is pulled at constant speed to the top of a 25 degrees hill.
zloy xaker [14]

Answer:

P=28.085\,hp

Explanation:

Given that:

  • mass of 1 skier, m=80kg
  • inclination of hill, \theta=25^{\circ}
  • length of inclined slope, l=220m
  • time taken to reach the top of hill, t=2.3 min= 138 s
  • coefficient of friction, \mu=0.15

<em>Now, force normal to the inclined plane:</em>

F_N=m.g.cos\theta

F_N=80\times 9.8\times cos25^{\circ}

F_N=710.54\,N

<em>Frictional force:</em>

f=\mu.F_N

f=0.15\times 710.54

f=106.58\,N

<em>The component of weight along the inclined plane:</em>

W_l=m.g.sin\theta

W_l=80\times 9.8\times sin25^{\circ}

W_l=331.33\,N

<em>Now the total force required along the inclination to move at the top of hill:</em>

F=f+W_l

F=106.58+331.33

F=437.91\,N

<em>Hence the work done:</em>

W=F.l

W=437.91\times 220

W=96340.80\,J

<em>Now power:</em>

P=\frac{W}{t}

P=\frac{96340.80}{138}

P=698.12\,W

<u>So, power required for 30 such bodies:</u>

P=30\times 698.12

P=20943.65\,W

P=\frac{20943.65}{745.7}

P=28.085\,hp

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What Lags harder than my Nokia
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my brain.

Explanation:

...................

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