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sweet-ann [11.9K]
3 years ago
5

Two bodies are falling with negligible air resistance, side by side, above a horizontal plane. If one of the bodies is given an

additional horizontal acceleration during its descent, it
a. strikes the plane at the same time as the other body
b. strikes the plane earlier than the other body
c. has the vertical component of its acceleration altered
d. has the vertical component of its velocity altered
e. follows a straight line path along the resultant acceleration vector
Physics
2 answers:
Elodia [21]3 years ago
8 0

Answer:

option (a) is correct.

Explanation:

one body has only vertical acceleration while the other has vertical and horizontal both the accelerations.

The time of fall of both the bodies is same

h = 0.5gt²

as initial vertical velocity for both the bodies is zero and the height from which they fall is same, so the time of fall for both the bodies is same.

Option (A) is correct.

borishaifa [10]3 years ago
4 0

Answer:a

Explanation:

Given

two bodies are falling with negligible air Resistance and one of the body is given a slight horizontal acceleration

since there is no change in vertical acceleration therefore time taken by both bodies is same irrespective of change in horizontal direction

suppose both start from rest from a height of h

time taken

t=\sqrt{\frac{2h}{g}}

The only difference is that body with horizontal acceleration will be some distance away from first                  

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The most recent evidence supporting the theory of plate tectonics would include A) GPS monitoring of plate speeds and movements.
Whitepunk [10]

A) GPS monitoring of plate speeds and movements.

Explanation:

The most recent evidence supporting the theory of plate tectonics would be GPS monitoring of plate speeds and movements.

A GPS is a Global Positioning System made up of series of components.

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3 years ago
A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then
Tasya [4]

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

Solution:

Parachutist feels air resistance of 800 N.

Thus, 800 N of force is acting in upward direction.

Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

F_{net} = 800-500

F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

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3 years ago
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A well-thrown ball is caught in a well-padded mitt. If the deceleration of the ball is 2.10×10^{4} 4 m/s^{2} 2 , and 1.85 ms (1
Paha777 [63]

Answer:

u = - 38.85 m/s^-1

Explanation:

given data:

acceleration = 2.10*10^4 m/s^2

time = 1.85*10^{-3} s

final velocity = 0 m/s

from equation of motion we have following relation

v = u +at

0 =  u + 2.10*10^4 *1.85*10^{-3}

0 = u + (21 *1.85)

0 = u + 38.85

u = - 38.85 m/s^-1

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6 0
3 years ago
A 1400 kg car traveling at 17.0 m/s to the south collides with a 4700 kg truck that is at rest. The car and truck stick together
STatiana [176]

Answer:

Final velocity = 7.677 m/s

KE before crash = 202300 J

KE after crash = 182,702.62 J

Explanation:

We are given;

m1 = 1400 kg

m2 = 4700 kg

u1 = 17 m/s

u2 = 0 m/s

Using formula for inelastic collision, we have;

m1•u1 + m2•u2 = (m1 + m2)v

Where v is final velocity after collision.

Plugging in the relevant values;

(1400 × 17) + (4700 × 0) = (1400 + 1700)v

23800 = 3100v

v = 23800/3100

v = 7.677 m/s

Kinetic energy before crash = ½ × 1400 × 17² = 202300 J

Kinetic energy after crash = ½(1400 + 1700) × 7.677² = 182,702.62 J

8 0
3 years ago
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