Answer:
0.17
Explanation:
Draw a free body diagram. There are five forces on the box:
Weight force mg pulling down
Normal force Fn pushing up
Applied force 52 N pulling to the left
Applied force 125 N pulling to the right
Friction force Fnμ pulling to the left
Sum of the forces in the y direction:
∑F = ma
Fn − mg = 0
Fn = mg
Fn = (45)(9.8)
Fn = 441
Sum of the forces in the x direction:
∑F = ma
125 − 52 − Fnμ = 0
Fnμ = 73
μ = 73 / Fn
μ = 73 / 441
μ = 0.17
Answer:
Explanation:
If Ig be moment of inertia about an axis through centre of mass and I be moment of inertia through any other axis parallel to earlier axis , then according to theory of parallel axis ,
I = Ig + Md²
where M is mass of the body and d is distance between two parallel axis.
So I is greater than Ig.
Answer:
a) V = 45 10³ V, b) U = 4.59 J
Explanation:
a) The electric potential for a series of point charges is
V = k ∑
in this case point P is at a distance of 1 m from each charge, so the point is located perpendicular to the charges at its midpoint
V = k ( )
V = 9 10⁹ (10 - 5/ 1) 10⁻⁶
V = 45 10³ V
b) the potential energy is
U = k ( )
where r = 1m and r₂ is the distance between the two charges r₂ = 0.10 m
U = 9 10⁹ (10 2 / 1 - 5 2/1 - 10 5 /0.10) 10⁻¹²
U = 9 10⁻³ 510
U = 4.59 J
There is no work because there is no displacement
answer: 0