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madreJ [45]
3 years ago
7

Which of the following statements are true? Check all that apply. Check all that apply. The gravitational force between two obje

cts is proportional to the square of the distance between the two objects. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects. The gravitational force between two objects is proportional to the distance between the two objects. The gravitational force between two objects is inversely proportional to the product of the masses of the two objects. The gravitational force between two objects is proportional to the product of the masses of the two objects. The gravitational force between two objects is inversely proportional to the distance between the two objects.
Physics
2 answers:
sashaice [31]3 years ago
5 0

Answer:

The gravitational force between two objects is proportional to the product of the masses of the two objects.

Explanation:

uysha [10]3 years ago
3 0

Explanation:

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :

F\propto \dfrac{m_1m_2}{r^2}

F=G \dfrac{m_1m_2}{r^2}...............(1)

Where m₁ and m₂ are masses

r is the distance between them

It is clear from equation (1) that :

1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.

2. The gravitational force between two objects is proportional to the product of the masses of the two objects.

Hence, this is the required solution.

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A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom o
Jet001 [13]

Answer:

C) 3,000 kg m/s

Explanation:

We can consider the horizontal velocity of the motorcycle to be zero, since it rolls off the edge of the cliff very slowly. So, we only need to find the vertical velocity at the time of the impact with the ground.

The vertical velocity of the motorcycle at time t is given by (free-fall motion):

v(t)=v_0 -gt

where

v_0=0 is the initial vertical velocity (zero, since the motorcycle is not moving)

g = 9.8 m/s^2 is the acceleration due to gravity

t is the time

Since the motorcycle hits the ground after t = 3 seconds, we have

v(3 s)=0-(9.8 m/s^2)(3 s)=-29.4 m/s

And since we know its mass, m=100 kg, we can find its momentum:

p=mv=(100 kg)(-29.4 m/s)=-2940 kg m/s \cdot -3000 kg m/s

and the negative sign simply means downward direction.

8 0
3 years ago
If mars has an orbital period of 1.84 years how far from the sun is it and how
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3 years ago
Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250
m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = \dfrac{\pi}{4}d^2

v = Terminal velocity = v=210\ m/s

s = Displacement = 150 m

a=\dfrac{v^2-u^2}{2s}

Force is given by

F = ma

F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0
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When balancing an equation, you can
attashe74 [19]
D. write down the coefficients
7 0
3 years ago
2.
juin [17]

Answer:

e.4

Explanation:

7 0
2 years ago
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