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madreJ [45]
3 years ago
7

Which of the following statements are true? Check all that apply. Check all that apply. The gravitational force between two obje

cts is proportional to the square of the distance between the two objects. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects. The gravitational force between two objects is proportional to the distance between the two objects. The gravitational force between two objects is inversely proportional to the product of the masses of the two objects. The gravitational force between two objects is proportional to the product of the masses of the two objects. The gravitational force between two objects is inversely proportional to the distance between the two objects.
Physics
2 answers:
sashaice [31]3 years ago
5 0

Answer:

The gravitational force between two objects is proportional to the product of the masses of the two objects.

Explanation:

uysha [10]3 years ago
3 0

Explanation:

The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Mathematically, it is given by :

F\propto \dfrac{m_1m_2}{r^2}

F=G \dfrac{m_1m_2}{r^2}...............(1)

Where m₁ and m₂ are masses

r is the distance between them

It is clear from equation (1) that :

1. The gravitational force between two objects is inversely proportional to the square of the distance between the two objects.

2. The gravitational force between two objects is proportional to the product of the masses of the two objects.

Hence, this is the required solution.

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A gas has a pressure of 48atm in a 15.5L container. It was found that at 25∘C the gas occupied a volume of 25L and had a pressur
EleoNora [17]

Answer:

130.165636364°C

Explanation:

P = Pressure

V = Volume

n = Number of moles

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From ideal gas law we have

PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{22\times 25}{0.082\times (25+273.15)}\\\Rightarrow n=22.496451696\ moles

PV=nRT\\\Rightarrow T=\dfrac{PV}{nR}\\\Rightarrow T=\dfrac{48\times 15.5}{22.496451696\times 0.082}\\\Rightarrow T=403.315636364\ K

The initial temperature is 403.315636364-273.15=130.165636364\ ^{\circ}C

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Let the displacement function of a particle is x(t)=(20t^2-15t+200). Find the total displacement, instantaneous velocity and ins
irga5000 [103]

Answer:

A.) 39.5 m

B.) 0

C.) 60m/s^2

Explanation:

Given that a displacement function of a particle is x(t)=(20t^2-15t+200).

To Find the total displacement,

Reduce everything by dividing them by 5

X(t) = 4t^2 - 3t + 40 ...... (1)

For instantaneous velocity, differentiate x(t). That is,

dy/dt = 60t - 15 ...... (2)

But dy/dt = velocity.

If dy/dt = 0, then

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60t = 15

t = 15/60

t = 0.25s

Substitutes t in equation (1)

Total displacement will be

X(t) = 4(0.25)^2 - 3(0.25) + 40

X(t) = 0.25 - 0.75 + 40

Total displacement = 39.5 m

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3 years ago
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