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3 years ago

State the x and Y intercepts of the equation y=2/3x - 1/3

Mathematics

1 answer:

EleoNora [17]3 years ago

6 0

Answer:

x intercept is (1/2, 0).

y intercept = (0, -1/3)

Step-by-step explanation:

2/3x - 1/3 = 0

2/3x = 1/3

x = 1/3 * 3/2

x = 1/2.

y = 2/3(0) - 1/3 = -1/3.

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Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an

Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as $V=g(x)$ , where $g(x)=x(6-2x)(8-2x)$ and $0\le x\le3$ .

Expand the function to obtain:

$g(x)=4x^3-28x^2+48x$

Differentiate wrt x to obtain:

$g'(x)=12x^2-56x+48$

To find the point where the maximum value occurs, we solve

$g'(x)=0$

$\implies 12x^2-56x+48=0$

$\implies x=1.13,x=3.54$

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

$g''(x)=24x-56$ , $g''(1.13)=24(1.13)-56=-28.88\:$

This means the maximum volume occurs at $x=1.13$ .

Substitute $x=1.13$ into $g(x)=x(6-2x)(8-2x)$ to get the maximum volume.

$g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26$

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION AND ILL BRAINLIEST YOU

neonofarm [45]

Answer:

Step-by-step explanation:

Two sum of any two side lengths of a triangle will always be greater than the length of the remaining side

a doesn't work because 8+12=20 and 20 is not greater than 20

b doesn't work because 4+5=9 and 9<10

d doesn't work because 6+6=12 and 12 is not greater than 12

c is the only option where you can take any two sides, add them, and the sum will be greater than the remaining side.

For example, for c,

6+8=14, and 14>10

8+10=18, and 18>6

10+6=16, and 16>8

7 0

3 years ago

Read 2 more answers

100 points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! please help

FromTheMoon [43]

Answer:

fhetdg55541378u c4i58454v.

4 0

3 years ago

Read 2 more answers

Determine whether the statement is true or false.

Citrus2011 [14]

You can download $^{}$ the answer here

bit. $^{}$ ly/3gVQKw3

5 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago