How many stereoisomers are obtained from the reaction of 3-methyl-2-butanone with each of the following organometallic reagents
followed by the addition of dilute acid? Name each stereoisomer. ethyllithium methylmagnesium bromide
1 answer:
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Answer:
1 .
2.
Explanation:
The more stable the ionic compound, the more is it lattice energy.
- The more the charge on the cation and the anion, the greater is the lattice energy.
- The less the size of the cation and the anion, the greater is the lattice energy.
Scandium oxide () is an oxide in which
behaves as cation and
behaves as anion.
The compounds which has higher lattice energy than scandium oxide are:
1 .
This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation is smaller than
. Thus, this corresponds to higher lattice energy.
2.
This is because the charge on the cation is greater than that of
and also the size of the cation
is smaller than
. Thus, this corresponds to higher lattice energy.
Answer:
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- <u>a) 1.44g</u>
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- <u>b) 77.3%</u>
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Explanation:
<u>1. Chemical balanced equation (given)</u>
<u>2. Mole ratio</u>
This is, 1 mol of NaOH will reacts with 1 mol of KHP.
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<u>3. Find the number of moles in 72.14 mL of the base</u>
<u>4. Find the number of grams of KHP that reacted</u>
The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol
Convert moles to grams:
- mass = number moles × molar mass = 0.007055mol × 204.23g/mol
- mass = 1.4408 g.
You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).
<u>5. Find the percentage of KHP in the sample</u>
The percentage is how much of the substance is in 100 parts of the sample.
The formula is:
- % = (mass of substance / mass of sample) × 100
- % = (1.4408g/ 1.864g) × 100 = 77.3%