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miskamm [114]
3 years ago
11

What happens when a glass rod is dipped in HCl and is brought near ammonia gas?

Chemistry
1 answer:
seropon [69]3 years ago
6 0
We get white fumes of Amonium Chloride.
HCL + NH3 gives NH4CL + H2
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The nucleus of an atom is _______________________ charged.
Gemiola [76]

Answer:

positivly charged

Explanation:

5 0
3 years ago
Read 2 more answers
What is the pH when the hydrogen ion concentration is 1 x 10-3 M?
Fynjy0 [20]

Answer:

e. 3

Explanation:

In order to solve this problem we need to keep in mind the definition of pH:

  • pH = -log[H⁺]

As stated by the problem, the hydrogen ion concentration, [H⁺], is 1x10⁻³ M.

As all required information is available, we now can <u>calculate the pH</u>:

  • pH = -log(1x10⁻³ M)
  • pH = 3

The correct option is thus e.

6 0
2 years ago
The main reason that cs2 has a higher boiling point than co2 is that cs2
OlgaM077 [116]

Explanation:

Inspite of having similar intermolecular forces, CS2 has a higher boiling point than CO2, since it has a greater molar mass. The potential energy of molecules reduces until a certain level as they get closer to each other. Although the polarity of both CO2 and CS2 are cancelled because of their linear structure.

4 0
3 years ago
How many atoms are there in 144g of sucrose, C12H22O11 or sugar molecules?
kati45 [8]

Answer:

2.53×10²³ atoms

Explanation:

To solve this, convert grams to moles and moles to atoms.

To convert grams to moles, use the molar mass of C₁₂H₂₂O₁₁ (342.296 g/mol).  Divide the mass by the molar mass to get moles.  Moles = 0.4207

To convert moles to atoms, use Avogadro's number (6.022×10²³ atoms/mol).  Multiply moles by Avogadro's number to get atoms.  Atoms = 2.53×10²³

8 0
3 years ago
Calculate the amount of heat required to raise the temperature of a 24 g sample of water from 9°C to 23°C.
borishaifa [10]

Answer:

1400KJ/mol⁻¹

Explanation:

Amount of heat required can be found by:

Q = m × c × ΔT

<em>Where m is the mass, c is the specific heat capacity (4.2KJ for water) and ΔT is the change in temperature.</em>

Q = 24 × 4.2 × (23 - 9)

= 24 × 4.2 × 14

=   1411.2KJ/mol⁻¹

= <u>1400KJ/mol⁻¹</u>  (to 2 significant figures)

7 0
3 years ago
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