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miskamm [114]
3 years ago
11

What happens when a glass rod is dipped in HCl and is brought near ammonia gas?

Chemistry
1 answer:
seropon [69]3 years ago
6 0
We get white fumes of Amonium Chloride.
HCL + NH3 gives NH4CL + H2
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A student climbed up the hill at a constant speed, stopped at the top, and then ran quickly down the other side.
Pavlova-9 [17]

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The Answer Is C

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7 0
3 years ago
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Which color of visible light has the highest energy?
DanielleElmas [232]

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Blue: Because violet really has the most and blue is based on violet!

Explanation:

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4 0
3 years ago
How to solve 2 and 3
GarryVolchara [31]
Use the Heat formula for both problems.

q=m*c*∆t

Where
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3 0
3 years ago
Without consulting Appendix B, arrange each group in order of decreasing standard molar entropy (S°). Explain.(b) NO₂(g), NO(g),
denpristay [2]

The decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

N₂ has lower standard molar entropy. This can be explained as this molecule consist of same atom.

While, Complexity increases from NO to NO₂(g). Therefore, the standard molar entropy of NO₂(g) is greater than NO.

Thus, we concluded that the decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

learn more about standard molar entropy:

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8 0
2 years ago
(c) Polar solutes were separated by hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase. How would
Lelu [443]

Answer:

(c) The retention time would be higher (d) The retention time would be lower.

Explanation:

For the polar solutes which were separated using the hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase, the retention time would be higher if eluent were changed from 80 vol% to 90 vol% acetonitrile in water.

However, for the polar solutes which were separated using the normal-phase chromatography on bare silica with methyl t=butyl ether and 2-propanol solvent, the retention time would be lower if the eluent were changed from 40 vol% to 60 vol% 2-propanol.

5 0
3 years ago
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