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4 years ago

The element mercury was first discovered on the Sun. a. True b. False

1 answer:

8 0

This statement is FALSE. Mercury was not first discovered in the sun. In fact, mercury or quicksilver was discovered by ancient Indians and Chinese even before 2000 BC. Its ores that are called cinnabar are used in traditional Chinese medicines. However, the effectiveness is not yet justified because of the toxicity of the element. Mercury is also used with thermometers both in clinical and lab uses. Nowadays, the use of it in thermometers is gradually disappearing because of its harmful properties. <span> </span>

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Discard the water from the first step and re-fill the tall drinking water glass with the chilled water. Then slowly pour a small

inna [77]

Answer:

The hot water remains at the top of chilled water.

Explanation:

The hot water remains at the top of chilled water because hot water has less denser as compared to chilled water. Due to higher density of chilled water, it remains at the bottom due to its greater mass while on the other hand, the hot freshwater goes upward and spreads at the top of the chilled water due to lower mass so when the hot water is added to the chilled water, hot water remains at the top.

6 0

3 years ago

How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?

netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

12 × 250 = 4.5 × V₂

3000 = 4.5 × V₂

Divide both side by 4.5

V₂ = 3000 / 4.5

V₂ = 667 mL

Finally, we shall convert 667 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

667 mL = 667 mL × 1 L / 1000 mL

667 mL = 0.667 L

Thus, the volume of the solution prepared is 0.667 L

3 0

3 years ago

HELP!!!!!!!!!!!!!!!! PRETTY PLEASE !!!!!!!!!!!!!!!!

I am Lyosha [343]

Answer:

B. 75.0 kPa

Explanation:

P1V1/T1=P2V2/T2

(x * 100 L)/(300 K)=(100 kPa * 50.0 L)/(200 K)

x=75.0 kPa

4 0

4 years ago

Read 2 more answers

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

3 0

4 years ago

What is the simplified value of the exponent expression 16^1/4

Sliva [168]

Answer: 2

Justitification:

1) Property:

$a^{(1/b)} = \sqrt[b]{a}$

Therefore:

$16^{1/4}= \sqrt[4]{16}$

2) 16 = 2⁴

3) Property

$\sqrt[n]{a^n} =a^{n/n}=a$

Therefore:

$\sqrt[4]{2^4} =2^{4/4}=2$

3 0

3 years ago