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Ilia_Sergeevich [38]
3 years ago
13

Which types of electromagnetic wave travels through space the fastest?

Physics
1 answer:
viva [34]3 years ago
7 0

Answer:

The electromagnetic wave that travels the fastest through space is gamma ray

Explanation:

Electromagnetic wave is a type of wave which does not require material medium for its propagation. Examples of electromagnetic waves according to increasing frequency of the waves are gamma ray, x-ray, ultra violet ray, infra red, visible light, micro wave and radio waves.

Frequency of a wave is inversely proportional to period of oscillation of the wave. The higher the frequency of a wave, the shorter the period of oscillation.  Gamma ray has the highest wave frequency in electromagnetic spectrum and shorter period of oscillation, thereby causing it to have the highest penetration power.

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Which statements did both Aristotle and Ptolemy assume? Check all that apply.
tensa zangetsu [6.8K]

Bodies in space traveled in circles.

The planets revolved around the Earth.

6 0
3 years ago
Read 2 more answers
Identify the frequency used by these broadcast media.<br><br> FM<br> AM<br> Television
Oliga [24]

Answer:

AM radio = 540 - 1650 KHz

FM radio = 88 to 108 MHz

Television = 54 to 216 MHz

7 0
4 years ago
Read 2 more answers
Prove(show) ''T=2π√(l/g)''​
Nonamiya [84]

Answer:

Time period for Simple pendulum, T=2\pi\sqrt{\frac{l}{g}

Explanation:

The Simple Pendulum

Consider a small bob of mass m is tied to extensible string of length l that is fixed to rigid support. The bob is oscillating in the plane about verticle.

       Let \theta is the angle made by string with vertical  during oscillation.

Vertical component of the force on bob, F=-mg\sin\theta

Negative sign shows that its opposing the motion of bob.

Taking \theta as very small angle then, \sin\theta\sim\theta

F=-mg\theta    

Let x is the displacement made by bob from its mean position ,

then, \theta=\frac{x}{l}

so, F=-mg\frac{x}{l}                ........(1)

Since, pendulum is in hormonic motion,

as we know, F=-kx

where k is the constant and k=m\omega^{2}

F=-m\omega^2x                   .........(2)

From equation (1) and (2)

-m\omega^2x=-mg\frac{x}{l}

\omega=\sqrt{\frac{g}{l}}

Since, \omega=\frac{2\pi}{T}

\frac{2\pi}{T}=\sqrt{\frac{g}{l}

T=2\pi\sqrt{\frac{l}{g}}

6 0
3 years ago
A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm? Check all that apply.
kherson [118]

Answer:

The answers are options B,D and E

Explanation:

B) The particles in the liquid are slowly overcoming the forces of attraction and spreading out due to the thermal energy they are absorbing. This makes the liquid less dense as it slowly changes into a gas after reaching its boiling point.

D) The particles start absorbing the energy form the surroundings as latent heat of evaporation. They need this energy to overcome the strong forces of attraction between particles to change into the gaseous state

E) The particles have spaced out due to the thermal energy absorbed, making the liquid lighter and it rises upwards.

5 0
3 years ago
You’re speeding at 85 km/hr when you notice that you’re only 10 m behind the car in front of you,
solmaris [256]
Your position in meters will, measured relative to the starting point of the car behind you, be 
x1(t) = 10 + 23.61 t - 1/2 4.2 t^2 
his position will be 
x2(t) = 16.67 t 
Hence at any time the separation s(t) will be 
s(t) = x1(t) - x2(t) = 10 + 6.94 t -2.1 t^2 
Now I assume you mean that you will decelerate UNTIl you are driving at the legal speed limit (60 km/h). That will take you: 
16.67 m/s = 23.61m/s - 4.2 m/s^2 * t 
t = 1.65 seconds 
What is the separation at that time? If it is still greater than zero, there will be no collision: 
s(1.65) = 10 + 6.94 *1.65 -2.1 (1.65)^2 = 15.73 meters. 
Hence you will NOT collide. The 1.65 s you calculated was the time needed to brake to the speed of 60 km/h. 
7 0
3 years ago
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