Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Step-by-step explanation:
0.2m^3 = 0.0000002 cm^3
Answer:
y = 2x + 14
Step-by-step explanation:
Hope this helps!!!
First, you have to find the slope by using
In other words,
The slope is 2.
Then you plug the rest into point-slope form (you can use either of the points, I used the first one)
Remember that m is the slope.
Distribute the slope to the parenthesis
Isolate the y variable
