1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8_murik_8 [283]
3 years ago
6

Maddie Cat can ride her tricycle at a speed of 3.75 meters per second. How far can she go in 5.0 seconds

Physics
1 answer:
lianna [129]3 years ago
8 0
3.75 x 5.0= 18.75 meters
You might be interested in
A heavy flywheel rotating on its central axis is slowing down because of friction in its bearings. At the end of the first minut
Soloha48 [4]

Answer:

ω₂ = 93.6 rev / min

Explanation:

ω₀ = 260 rev / min

ω₁ = 0.68*ω₀ = 0.68*(260 rev / min) = 176.8 rev / min

ω₂ = ?

t₁ = 1 min

t₂ = 2 min

We can apply the equation:

ω₁ = ω₀ + α*t₁     ⇒    α = (ω₁ - ω₀) / t₁  

⇒   α = (176.8 rev / min - 260 rev / min) / 1 min = - 83.2 rev / min²

then we can use the same formula, knowing the angular acceleration:

ω₂ = ω₀ + α*t₂   ⇒   ω₂ = (260 rev / min) + (- 83.2 rev / min²)*(2 min)

⇒   ω₂ = 93.6 rev / min

6 0
3 years ago
If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev
soldi70 [24.7K]

Answer:

5.22m/s^2

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

X = \frac{2.4 * 100\%} { 4 }= 60\%

In this way it would mean that the body could be driven to 60% of its total.

So

Speed_{Decreased} = 8.7 * 60\% = 5.22 \frac{m}{s^2}

3 0
3 years ago
a motorcyclist starts from rest and accelerates at rate of 4 meters per second squared north. what is the final velocity of the
MArishka [77]

Answer:

80m<em>/</em><em>s</em>

Explanation:

Final velocity is given by

v=u+at

when a motorcyclist starts from rest, initial velocity (u) =0

therefore

v=0+4*20

v=80m/s

that's the answer

8 0
4 years ago
A body is traveling at 5.0 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion s
loris [4]

To solve this problem it is necessary to apply the concepts related to the conservation of momentum and conservation of kinetic energy.

By definition kinetic energy is defined as

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

On the other hand we have the conservation of the moment, which for this case would be defined as

m*V_i = m_1V_1+m_2V_2

Here,

m = Total mass (8Kg at this case)

m_1=m_2 = Mass each part

V_i = Initial velocity

V_2 = Final velocity particle 2

V_1 = Final velocity particle 1

The initial kinetic energy would be given by,

KE_i=\frac{1}{2}mv^2

KE_i = \frac{1}{2}8*5^2

KE_i = 100J

In the end the energy increased 100J, that is,

KE_f = KE_i KE_{increased}

KE_f = 100+100 = 200J

By conservation of the moment then,

m*V_i = m_1V_1+m_2V_2

Replacing we have,

(8)*5 = 4*V_1+4*V_2

40 = 4(V_1+V_2)

V_1+V_2 = 10

V_2 = 10-V_1(1)

In the final point the cinematic energy of EACH particle would be given by

KE_f = \frac{1}{2}mv^2

KE_f = \frac{1}{2}4*(V_1^2+V_2^2)

200J=\frac{1}{2}4*(V_1^2+V_2^2)(2)

So we have a system of 2x2 equations

V_2 = 10-V_1

200J=\frac{1}{2}4*(V_1^2+V_2^2)

Replacing (1) in (2) and solving we have to,

200J=\frac{1}{2}4*(V_1^2+(10-V_1)^2)

PART A: V_1 = 10m/s

Then replacing in (1) we have that

PART B: V_2 = 0m/s

8 0
3 years ago
What pieces of information do you need to accurately describe the motion of an object?
Vlad [161]

An object's location, velocity, acceleration, and direction can all be used to define motion.

Define velocity:

Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the quickest when their motion is in the other direction. The idea of velocity is useful in these circumstances. Learn what velocity is, how it is measured, an example of velocity, and how it differs from speed in this article.

Motion may be described using an object's position, velocity, acceleration, and direction.

To learn more about motion follow the given link:
brainly.com/question/26083484

#SPJ1

5 0
1 year ago
Other questions:
  • In the braking test of a sports car, its velocity is reduced from 70 mi/h to zero in a distance of 180 ft with slipping impendin
    15·1 answer
  • Using a good pair of binoculars, you observe a section of the sky where there are stars of many different apparent brightnesses.
    12·1 answer
  • Which factors are most likely to affect whether a galaxy will evolve by merging with a second galaxy? Select the two correct ans
    10·1 answer
  • Which of the following is NOT usually published with a scientific report?
    11·1 answer
  • 4a.) A 0.50 kg water balloon is thrown against a wall at 32 m/s coming to a stop. What was its change in
    6·1 answer
  • 15. A spring has a constant of 152 when a force of 50.92 N is applied to it. How far did the spring stretch?
    5·1 answer
  • To calculate the gravitational potential energy of a statue on a 10-meters-tall platform, you would have to know the statue's __
    10·1 answer
  • What do is mean by environment friendly behaviour?​
    10·1 answer
  • A train leaving the station accelerates from a full stop at a rate of 0.250 meters per second squared for 45.0 seconds. How far
    5·1 answer
  • What is the penetration depth β−-radiations in Aluminium in cm? Can you determine the
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!