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The correct expression for the maximum speed of the object during its motion is .
The maximum speed of the object is determined using the following formulas;
v(max) = Aω
where;
- A is the amplitude of the motion
- ω is angular speed
The maximum speed of the object can also be obtained from the maximum net force on the object,
F = ma
where;
- F is the maximum net force
- a is the acceleration
- m is mass of the object
F = m(v/t)
mv = Ft
v = Ft/m
Thus, the correct expression for the maximum speed of the object during its motion is .
Learn more about maximum speed here: brainly.com/question/4931057
Answer:
μ = 0.423
Explanation:
To solve this exercise we must use Newton's second law and kinematics together, let's start using expressions of kinematics to find the acceleration of the body
Let's fix a reference system where the x axis is parallel to the inclined plane, but the acceleration is only on this axis
x = v₀ t + ½ a t²
The body starts from rest so its initial speed is zero
a = 2 x / t²
a = 2 0.5 /0.5²
a = 4 m / s²
Taking the acceleration of the body, we use Newton's second law, we take the direction up the plane as positive
X axis
fr - Wₓ = m a (1)
Y Axis
N- = 0
N = W_{y}
We use trigonometry to find the components of the weight
sin 45 = Wₓ / W
cos 45 = W_{y} / W
Wₓ = W sin 45
W_{y} = W cos 45
The out of touch has the expression
fr = μ N
fr = μ W_{y}
We substitute in 1
μ mg cos 45 - mg sin 45 = m a
W_{y} = (a + g sin 45) / g cos 45
μ = a / g cos 45 + 1
We calculate
Acceleration goes down the plane, so it is negative
a = -4 m / s²
μ = 1- 4 / (9.8 cos 45)
μ = 0.423