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Hatshy [7]
2 years ago
12

20 Points available for physics help

Physics
2 answers:
Sonja [21]2 years ago
8 0
The second one is correct not sure about the first one sorry
Sedaia [141]2 years ago
8 0

Answer: 2

Explanation:

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Negative charges repel positive charges.<br> a. true or<br> b. false
arlik [135]
False they attract.. Remember opposites attract!
6 0
2 years ago
Energy Calculations
MaRussiya [10]

Answer: 20,734.69 N/m

Explanation:

The elastic potential energy (ELPE) of the rubber band is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x = 0.035 m is the stretching of the rubber band

E = 12.7 J is the ELPE of the rubber band

Substituting the numbers and re-arranging the equation, we find

k=\frac{2E}{x^2}=\frac{2\cdot 12.7 J}{(0.035 m)^2}=20,734.69 N/m

6 0
2 years ago
A 16.7 kg block is dragged over a rough, horizontal surface by a constant force of 132 N acting
Alisiya [41]

The magnitude of the work done by the force of friction is 1045.68 joules

Explanation:

Work done = force × distance

  • Work done by friction force (W) = friction force (F) × distance (d)
  • Friction force (F) = coefficient of  kinetic friction (μ) × normal reaction force (R)

A 16.7 kg block is dragged over a rough, horizontal surface by a constant force of 132 N acting  at an angle of 25.8. above the horizontal. The block is displaced 57,8 m, and the coefficient of  kinetic friction is 0.229

To find the normal reaction force of the block distribute The constant force into two component, horizontal component of 132 cos(25.8°) and vertical component 132 sin(25.8°), Then equate ∑vertical forces by 0 to find R

The weight of the block = mg, where m is its mass and g is 9.8 m/s²

→ ∑Vertical forces = R + 132 sin(25.8°) - mg

→ ∑Vertical forces = R + 132 sin(25.8°) - (16.7)(9.8)

→ ∑Vertical forces = R - 106.2

Equate it by 0

→ R - 106.2 = 0 ⇒ add 106.2 to both sides

→ R = 106.2 N

Now let us find the friction force

→ F = μ R

→ μ = 0.229

→ F = 0.229 (106.2) = 24.3198 N

Let us calculate the work don by the force of friction

→ W = F × d

→ d = 57.8 meters

→ W = 24.3198 × 57.8 = 1045.68 joules

The magnitude of the work done by the force of friction is 1045.68 joules

Learn more:

You can learn more about force of friction in brainly.com/question/6217246

LearnwithBrainly

6 0
3 years ago
The resultant of two vectors is maximum, when angle between them is:
dexar [7]
When angle between them is zero
7 0
3 years ago
Which of the following provides evidence that there must be at least two types of electrical charge, but that there is only one
polet [3.4K]

Answer:

Option D (On the...............dominate) would be the right approach.

Explanation:

The Gravitational constant (G) will be:

= 6.67\times 10^{-11}

The Coulomb's law constant (K) will be:

= 9\times 10^9

  • Throughout particular, these have been determined that among 2 substances with almost the similar form of charge, the combination of electromagnetic as well as the force does seem to be usually the following:

⇒ \frac{f_e}{f_g}\sim 10^{42}

  • By that same argument, the electrostatic force including its planet's atmosphere would have strongly influenced the effect, as well as maybe the planet's atmosphere, would have crashed, or perhaps the earth would have shifted at a much longer exposure from one another and.
  • Throughout particular, astronomical distance statutory framework that gravity seems to be predominant, whereas electrostatic forces have been generally ignored. It is quite since there are so many categories of allegations throughout the planet's atmosphere that balance out someone else's effects, there's only yet another form of momentum, because although the forces are still cumulative, as well as therefore offering to help everything hold to the universe, encouraging the universe just to rotate across the sun.

The latter three choices aren't connected to either the situation mentioned in the clarification segment elsewhere here.

5 0
3 years ago
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