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melomori [17]
3 years ago
6

Ok! Water is added to 200. ml of a 2.0 M solution of CaCI2 to increase the volume of the solution to 450. ml. So what is the new

concentration?
Chemistry
1 answer:
dexar [7]3 years ago
7 0

Answer:

0.89M

Explanation:

Because moles of solute do not change, we can write

M1V1 = M2V2

M - molarity, V - volume of solution

2.0M*200mL = M2*450mL

M2 = 0.89 M

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Write a note on Polygenic disorder.​
Lorico [155]

Answer:

a note? well alright

Explanation:

<em><u>Polygenic disease:</u></em>  (the defintion)

A genetic disorder that is caused by the combined action of more than one gene.

<u>Polygenic conditions</u><u>:</u> hypertension, coronary heart disease, and diabetes.

This is so because such disorders depend on the simultaneous presence of several genes, they are not inherited as simply as are single-gene diseases.

8 0
3 years ago
Is the atomic number the lesser or the greater of the numbers for each atom on the periodic table?
SOVA2 [1]
Lesser. atomic number means proton number
3 0
3 years ago
please help i dont get chemistry as much as I've only just started and I dont know how to separate all these matters ​
dsp73

is this technical chemistry?

6 0
3 years ago
A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40
Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = 40 hr/week\times 8 week = 320 hours

The concentration of xylene in the workplace =40 \mu g/m^3

The worker is inhaling air at a rate of 0.9 m^3/hr.

Amount xylene inhaled by worker in an hour :

= 40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr

Amount xylene inhaled by worker in 320 hours:

36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

\frac{24}{320}\times 11.520 mg=0.864 mg

Assuming 70 kg body mass, the chronic daily intake of xylene :

\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0
3 years ago
A sample of a pure element has a mass of 45.6g and contains 4.19 x 10 23 atoms. Identify the element.
max2010maxim [7]
<h2>Answer:</h2>

    ZINC

<h2>Explanation:</h2>

<em>To identify the element based on the informartion given, we have to find the molar mass since this mass is unique to each element.</em>

            Molar mass = mass ÷ moles

<em>We already know the mass based on the question, as such we now need to find the # of moles.</em>

           Since 1 mole contains 6.02214 × 10²³ atoms

      then let  x moles contain 4.19 × 10²³ atoms <em>(given in the question)</em>

<em>     </em><em> </em>   ⇒   x =  (4.19 × 10²³ atoms  ×  1 mol) ÷ 6.02214 × 10²³ atoms

              x  =  0.69577 mol

<em>Now that we have the moles we can substitute it into the molar mass equation and solve for the molar mass.</em>

           ⇒ molar mass = 45.6 g ÷ 0.69577 mol

           ⇒ molar mass ≈  65.54 g/mol

                    This molar mass is closest to that of ZINC.

7 0
3 years ago
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