The correct name of the compound Mn3(PO4)2 is definitely the last option represented above <span>D. manganese(II) phosphate. I am pretty sure this answer will help you
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First you need to calculate the number of moles of aluminium and copper chloride.
number of moles = mass / molecular weight
moles of Al = 512 / 27 = 19 moles
moles of CuCl = 1147 / 99 = 11.6 moles
From the reaction you see that:
if 2 moles of Al will react with 3 moles of CuCl
then 19 moles of Al will react with X moles of CuCl
X = (19 × 3) / 2 = 28.5 moles of CuCl, way more that 11.6 moles of CuCl wich is the quantity you have. So the copper chloride is the limiting reagent.
Since the half life of the radioactive isotope is 4,000 years, after 4,000 years the amount of the isotope would decrease by half. (Hence the name, half life.) So, after 4,000 years, there would be half of the isotope left in the fossil.
Answer:
<h3>The answer is 11 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 2.75 kg = 2750 g
volume = 250 cm³
We have
We have the final answer as
<h3>11 g/cm³</h3>
Hope this helps you
There are 2 Ca, 4 H (2*2) and 4 O (2+2) on the left hand side. So there should be the same number of atoms 2Ca and 4(O+H) on the right hand side. The reaction is a synthesis (making something new), rather than a decomposition (destroying something).
The answer is Two molecules of Ca(OH)2 should be produced during the synthesis reaction.
