Answer:
1.058337 grams of hydrogen and 2H2 + O2 ==> 2H2O hydrogen peroxide
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
and it could also produce H2O water but no air but it could make other things
The balanced chemical reaction would be as follows:
<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10
We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:
8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2
Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:
0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
<span>any electrolyte that is not easily reduced or oxidized</span>
<h3>Answer:</h3><h2>Equilibrium constants are changed if you change the temperature of the system. Kc or Kp are constant at constant temperature, but they vary as the temperature changes. You can see that as the temperature increases, the value of Kp falls.</h2>
