Which statement correctly describes the gravitational potential energy of the pendulum based on this diagram?
1 answer:
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Answer:
389.78681 K
Explanation:
= Initial pressure = 55.1 mmHg
= Final pressure = 1 atm = 760 mmHg
= Boiling point
= Initial temperature = 35°C
= Heat of vaporization = 32.1 kJ/mol
From the Clausius-Claperyon equation
The normal boiling point of the substance is 389.78681 K
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
<u>Velocity = 0.4762 m/s</u>