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Artemon [7]
3 years ago
5

A tree limb of mass 12 kg falls straight down. If air resistance exerts 27 N of force on the limb as it falls, what is the net f

orce on the tree limb
Physics
2 answers:
Mandarinka [93]3 years ago
8 0

Answer: 91N down

Explanation:

Karolina [17]3 years ago
6 0

The net force is 27 n

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A wave has a wave length of 20mm and a frequency of 5 hertz. What is the speed?
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Speed = (wavelength) x (frequency

Speed = (.020 m) x (5 / sec)

Speed = 0.1 m/s
7 0
2 years ago
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If the volume on your TV is low, turning the volume up one click of the remote control will make the TV seem louder than if the
marusya05 [52]

From what we know, we can confirm that this ratio (turning up the volume by one click relative to the TV's overall volume) can be quantified as the Weber fraction.

<h3>What is the Weber fraction?</h3>

This fraction describes the ratio needed for change to a stimulus in which the change is just barely noticeable. This question is a prime example in that it seeks to find out just how low of a difference is needed in TV volume in order for the difference to be noticeable.

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brainly.com/question/5004433?referrer=searchResults

7 0
2 years ago
The spectra of most galaxies show redshifts. this means that their spectral lines _________.
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Have wavelengths that are longer than normal.
3 0
3 years ago
How is this formula ( Rt= r1 x r2 / r1 + r2) which is used to calculate total resistance of two parallel resistors found from th
Maru [420]

Explanation:

The total resistance used to calculate the total resistance of the two parallel resistor is given by :

R_t=\dfrac{r_1\times r_2}{r_1+r_2}

Taking reciprocal of the above equation.

\dfrac{1}{R_t}=\dfrac{r_1+r_2}{r_1\times r_2}

We can also write the above equation as :

\dfrac{1}{R_t}=\dfrac{r_1}{r_1\times r_2}+\dfrac{r_2}{r_1\times r_2}

On simplification of above equation,

\dfrac{1}{R_t}=\dfrac{1}{r_2}+\dfrac{1}{r_1}

or

\dfrac{1}{R_t}=\dfrac{1}{r_1}+\dfrac{1}{r_2}

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4 0
2 years ago
Alan leaves Los Angeles at 8:00 A.M. to drive to San Francisco 400 mi away. He manages to travel at a steady 50 mph in spite of
Fudgin [204]

Answer:

a) Beth will reach before Alan

b)Beth has to wait 20 min for Alan to arrive

Explanation:

let 'd' be distance b/w Los Angeles and San  Francisco i.e 400 mi

considering ,

Alan's speed v_A=50mph

Beth's speed v_B=60mph

->For Alan:

The time required t_A= d/v_A= 400/50 => 8h

-> For beth:

The time required t_B=\frac{d}{v_B} =\frac{400}{60} =>6\frac{2}{3} h => 6h 40m

Alan will reach at 8:00 a.m +8h = 4:00p.m.

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a) Beth will reach before Alan

b)Beth has to wait 20 min for Alan to arrive

3 0
3 years ago
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