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Zolol [24]
3 years ago
5

What is the total number of valence electrons in the dot structure of CBr4? Explain how you determined this answer. What is the

name of the 3-dimensional shape this molecule forms? (you may figure this out on scrap paper and just write the correct answer)
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:- There are 32 valence electrons and it's tetrahedral in shape.

Explanations:- Atomic number of carbon is 6 and it's electron configuration is 1s^22s^22p^2 . It has 4 electrons in the outer most shell means it has 4 valence electrons.

Atomic number of Br is 35 and it's electron configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5 . It has 7 electrons in the outer most shell(2 in 4s and 5 in 4p) .

There is one C and four Br in the given compound. So, total number of valence electrons = 4+4(7) = 4+28 = 32

Four Br atoms are bonded to the central carbon atom and also there isn't any lone pair present on carbon. It makes it tetrahedral.

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3 0
3 years ago
Fill in the blank
barxatty [35]

<em>Same group element have same</em><em><u> Valence electron</u></em><em> and behave similarly in </em><em><u>Chemistry.</u></em>

<u>Explanation:</u>

For example. First group elements Alkali metals:- H, Li, K, Rb, Cs, Fr

Valance electron will take part in forming a bond with other elements and compound will form. All the above-given elements (H-Fr) have valence electron 1 in outer most 'S' shell. All have electronic configuration S1

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4 0
3 years ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
A substance has a solubility of 350 ppm.how many grams of the substance are present in 1.0l of a saturated solution
sergeinik [125]
Since the given solubility is 350 ppm, convert it first with fraction of solubility. by dividing the solubility with 10^6
S = 350 / 10^6
s = 3.5 x 10^-4
the multiply it to the total solution to calculate the amount of substance present
m = ( 3.5 x 10^-4 ) ( 1.01 )
m = 3.535 x 10^-4 g of the substance present
6 0
3 years ago
Read 2 more answers
Once molecules are close enough to touch, intermolecular forces are
kiruha [24]
Once molecules are close enough to touch, intermolecular forces become replusive in order to prevent the molecules from overlapping.
8 0
3 years ago
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