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miv72 [106K]
3 years ago
12

During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/mi

n 227 g/min 908 g/min 13,600 g/min
Chemistry
1 answer:
Eduardwww [97]3 years ago
3 0
The solution for this problem would be:
The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min 
So solving for the rate will be mass over t = m/t = 227/0.25 = 908 g/min would be the answer for this problem.
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Can someone answer a and b to the file attached?
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