Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given:
= 105 L,
,
= 985 torr
At standard conditions,
= 273 K,
= 760 K,
= ?
Formula used to calculate the volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.
Answer:
graphite
Explanation:
Graphite is opaque, a very good lubricant, a good conductor of electricity, and a thermal insulator. Allotropes of carbon are not limited to diamond and graphite, but also include buckyballs (fullerenes), amorphous carbon, glassy carbon, carbon nanofoam, nanotubes, and others.
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Answer : The molal freezing point depression constant of liquid X is, 
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of liquid X (solvent) = 450 g = 0.450 kg
Molar mass of urea = 60 g/mole
Formula used :

where,
= change in freezing point
= freezing point of solution = 
= freezing point of liquid X = 
i = Van't Hoff factor = 1 (for non-electrolyte)
= Molal-freezing-point-depression constant = ?
m = molality
Now put all the given values in this formula, we get


Therefore, the molal freezing point depression constant of liquid X is, 