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drek231 [11]
3 years ago
12

In a nonpolar covalent bond,

Chemistry
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

#11: In a nonpolar covalent bond, electrons are shared equally between two atoms.

#12: Only the diatomic nitrogen molecule \rm N_2 contains a triple covalent bond among the four molecules.

Explanation:

<h3>#11</h3>

Consider: what is a covalent bond?

Two atoms share a pair of electrons (called a bonding pair as opposed to a lone pair) between them.

Nonpolar covalent bonds exist only between atoms with similar electronegativity values. The two bonding atoms attract the bonding pair with similar strength, such that the bonding pair is shared mostly equally between the two atoms.

In case the two atoms differ in their electronegativity, the bonding pair will be closer to the more electronegative atom. That will make a polar covalent bond.

<h3>#12</h3>

Atoms share electrons with each other to achieve an octet of eight valence electrons (two for hydrogen.) Atoms form a covalent bond for every two valence electrons that they need.

Consider: how many electrons do atoms in each molecule need to gain before achieving an octet?

Fluorine is in group 17 of the new IUPAC periodic table. Each fluorine atom needs 18 - 17 = 1 valence electron to achieve an octet. There are two fluorine atoms in an \rm F_2 molecule. These two atoms will need two electrons in total to achieve an octet. They will thus need to form 2/2 = 1 covalent bond.

Similarly:

  • Nitrogen is in group 15.
  • Each Nitrogen atom is 18 - 15 = 3 electrons away from an octet.
  • There are two nitrogen atoms in each \rm N_2 molecule.
  • The two nitrogen atoms need six more electrons in total and will form 6/2 =3 covalent bonds.
  • Oxygen is in group 16.
  • Each oxygen atom is 18 - 16 = 2 electrons away from an octet.
  • There are two oxygen atoms in each \rm O_2 molecule.
  • The two oxygen atoms need four more electrons in total and will form 4/2 =2 covalent bonds.
  • Hydrogen is a special case in the "octet" rule.
  • Each hydrogen atom needs one valence electron to attain the electron configuration of the next noble gas element, He.
  • There are two hydrogen atoms in each \rm H_2 molecule.
  • The two hydrogen atoms need two more electrons in total and will form 2/2 =1 covalent bonds.
Inga [223]3 years ago
7 0

Answer:

11.  Electrons are shared equally by two atoms.

12. Diatomic nitrogen

Explanation:

An example of  the  the first  bond is the diatomic hydrogen.

There are 5  electrons in the nitrogen atom's outer shell. The 2 nitrogen atoms will each share 3 electrons to form 3 covalent bonds.

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How many grams of hydrochloric acid are produced when 15.0 grams NaCl react with excess H2SO4 in the reaction
e-lub [12.9K]

Answer:

11.65 g

Explanation:

Amount of NaCl  = 15.0 grams

amount of H₂SO₄ = Excess

mass of hydrochloric acid (HCl) = ?

Solution:

To solve this problem first we will look for the reaction that NaCl react with  H₂SO₄

Reaction:

         2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄

As the  H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.

Now if we look at the reaction

         2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄

           1 mol                              2 mol  

Now convert moles to mass

Then

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

So,

            2NaCl           +      H₂SO₄     -------->       2HCl        +     Na₂SO₄

      2 mol (58.5 g/mol)                                    2 mol (36.5 g/mol)

              94 g                                                           73 g

So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl

For this apply unity formula

           94 g of NaCl  ≅ 73 g of HCl

           15.0 g of NaCl  ≅ X g of HCl

By Doing cross multiplication

           X g of HCl = 73 g x 15.0 g / 94 g

           X g of HCl = 11.65 g

11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl

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Explanation:

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4 0
3 years ago
If 20.0 g acetylene is allowed to completely react with oxygen, how many grams of o2 are reacted? 2c2h2(g 5o2(g → 4co2(g 2h2o(g
KATRIN_1 [288]
The balanced chemical reaction is written as:

<span>2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)

We are given the amount of acetylene to be used in the reaction. This will be the starting point for the calculations.

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dexar [7]

Answer:

By using the techniques of archeology.

Explanation:

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2 years ago
What is the half life of a compound if 75% of a given sampleof
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Answer:

t_{1/2}=30.14\ min

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

75 % is decomposed which means that 0.75 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.75 = 0.25

t = 60 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.25=e^{-k\times 60}

k = 0.023 min⁻¹

Considering the expression for half life as:-

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

t_{1/2}=\frac{\ln 2}{0.023}\ min

t_{1/2}=30.14\ min

5 0
2 years ago
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