Answer:
The Answer is D)
Step-by-step explanation:
Pare a.) $70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.
Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.
Answer:
(1,3)
Step-by-step explanation:
y = 2x+1
y = 4x-1
Since both equations are equal to y, we can set them equal to each other
2x+1 = 4x-1
Subtract 2x from each side
2x+1-2x = 4x-2x-1
1 = 2x-1
Add 1 to each side
1+1 = 2x-1+1
2 = 2x
Divide each side by 2
2/2 = 2x/2
1 =x
Now we need to find y
y = 2x+1
y = 2(1)+1
y =3
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
a polygon with seven sides is called a heptagon
