The first thing you should know is that the work is defined as:
W = F * d
Where
F = force
d = displacement
We have then
(a) the block
F = (0.2) * (100) = 20
d = 100
W = (20) * (100) = 2000 ft.lbf
(b) the man as the system.
F = (0.2) * (100 + 180) = 56
d = 100
W = (56) * (100) = 5600 ft.lbf
answer:
(a) 2000 ft.lbf
(b) 5600 ft.lbf
Sound is an example of a mechanical wave. Mechanical waves are the kinds of waves that cannot be propagated without a medium. As such, these waves cannot travel through a vacuum, just like how sound cannot travel through space, since space is a vacuum.
Answer:
a) P1=100kpa
V1=6m³
V2=?
P2=50kpa
rearranging mathematically the expression for Boyle's law
V2=(P1V1)/P2=(100×6)/50=12m³
b) same apartment as in (a) but only the value of P2 changes
=> V2=(100×6)/40=15m³
Explanation:
since temperature is not changing we use Boyle's law. mathematically expressed as P1V1=P2V2
Answer:
m = 9795.9 kg
Explanation:
v = 35 m/s
KE = 6,000,000 J
Plug those values into the following equation:
![KE = \frac{1}{2} mv^{2}](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D)
6,000,000 J = (1/2)(35^2)m
---> m = 9795.9 kg
Answer:
Explanation:
In a L C R circuit, the average power is given by
![P_{av}=V_{rms}I_{rms}Cos\phi](https://tex.z-dn.net/?f=P_%7Bav%7D%3DV_%7Brms%7DI_%7Brms%7DCos%5Cphi)
As given in the question
CosФ = R / Z
And we know that
![V_{rms}=I_{rms}\times Z](https://tex.z-dn.net/?f=V_%7Brms%7D%3DI_%7Brms%7D%5Ctimes%20Z)
So
![P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}](https://tex.z-dn.net/?f=P_%7Bav%7D%3DI_%7Brms%7D%5Ctimes%20Z%5Ctimes%20I_%7Brms%7D%5Ctimes%20%5Cfrac%7BR%7D%7BZ%7D)
![P_{av}=I_{rms}^{2}\times R](https://tex.z-dn.net/?f=P_%7Bav%7D%3DI_%7Brms%7D%5E%7B2%7D%5Ctimes%20R)