The key to solve this problem is the conservation of momentum. The momentum of an object is defined as the product between the mass and the velocity, and it's usually labelled with the letter
:
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The total momentum is the sum of the momentums. The initial situation is the following:

(it's not written explicitly, but I assume that the 5-kg object is still at the beginning).
So, at the beginning, the total momentum is
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At the end, we have

(the mass obviously don't change, the new velocity of the 15-kg object is 1, and the velocity of the 5-kg object is unkown)
After the impact, the total momentum is
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Since the momentum is preserved, the initial and final momentum must be the same. Set an equation between the initial and final momentum and solve it for
, and you'll have the final velocity of the 5-kg object.
Answer:
Japanese created earthquake proof buildings
Explanation:
Countries like Japan where earthquakes are regular. So these important factors are downgraded to nice -to-haves behind the need of Japan structural stability. The Pacific ring of Fire and all its seismic activities are contributed to Japans strict building codes for skyscrapers and Towers. Building codes means, earthquakes proof structures are intended to withstand the earthquake.The prime example of an earthquake-ready country is Japan with its dedication to structural stability.
5 great examples are
1. Mori Tower
2. Tokyo Skytree
3. Ark Hills Sengokuyama
4.fa-bo
5. Television House
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038
There's the acceleration of the car that provides a force and the normal force of the seat cushion which pushes upwards against the passenger
Answer:
Explained
Explanation:
public int dimension(int [][]a2d,int nElements)
{
int count = 0;
for(int i = 0;i < a2d.length ; i++)
{
count = count + a2d[i].length;
}
return count;
}