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4 years ago

Select the correct answer from each drop-down menu.

Chemistry

2 answers:

nataly862011 [7]4 years ago

8 0

The arrow shows that the bond between the chlorine atom and the fluorine atom is nonpolar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

Explanation:

The bond between Chlorine and fluorine is nonpolar bonding because both of them are sharing an equal number of electrons in the bond. H2, F2, and CL2 are common examples of this.

Chlorine and fluorine are electronegative molecules but Fluorine is above chlorine in the periodic table. Since fluorine is above Chlorine, fluorine has slightly highest electronegative nature compare to fluorine. This is the reason why Fluorine molecules are attracting electrons more than chlorine atoms. This making chlorine atoms slightly positive in Cl and F bonding.

Olin [163]4 years ago

5 0

Answer:

The arrow shows that the bond between the chlorine atom and the fluorine atom is polar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl.

The covalent bond between two atoms can be polar or nonpolar. This depends on the type of atoms that make it up: if the atoms are equal, the bond will be nonpolar (since no atom attracts electrons more strongly). But, if the atoms are different, the bond will be polarized towards the most electronegative atom, because it will be the atom that attracts the electron pair with more force. Then it will be polar.

So in this case, being two non-metallic elements, it is a covalent bond, and, following the definition previously presented, it is a polar bond, indicated by the arrow shown in the image.

The arrow also indicates that the atoms shared between both elements are more strongly attracted by F, due to the fact that it has a higher electronegativity. And since the electrons are negatively charged, fluorine will have a slightly negative charge, while chlorine will have a slightly positive charge.

So, finally, the arrow shows that the bond between the chlorine atom and the fluorine atom is polar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

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the bond formed between the carboxylic acid group of one amino acid and the amino group of the next amino acid is a(n) bond.

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1 year ago

A compound contains 64.27% carbon, 7.19% hydrogen, and 28.54% oxygen. the molar mass is 168.19 g/mol. what is the molecular form

coldgirl [10]

Empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of compound
C H O
mass 64.27 g 7.19 g 28.54 g
number of moles 64.27 g / 12 g/mol 7.19 g/1 g/mol 28.54 g / 16 g/mol
= 5.356 mol = 7.19 mol = 1.784 mol
divide by least number of moles
5.356 / 1.784 7.19 / 1.784 1.784 / 1.784
= 3.002 4.03 = 1.000
rounded off to nearest whole number
C - 3
H - 4
O - 1
empirical formula - C₃H₄O

mass of empirical formula = 12 g/mol x 3 + 1 g/mol x 4 + 16 g/mol x 1 = 56 g
molecular mass = 168.19 g/mol
molecular formula is the actual ratio of elements making up the compound
number of empirical units = molar mass of molecule / empirical mass
empirical units = 168.19 g/mol / 56 g = 3.00
there are 3 empirical units making up the molecular formula
molecular formula = 3 x C₃H₄O

molecular formula = C₉H₁₂O₃

5 0

4 years ago

A gram of gasoline produces 45 kJ of energy when burned. Gasoline has a density of 0.77 g/mL. How would you calculate the amount

BigorU [14]

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4 0

3 years ago

Convert 4.57X-3m to the equivalent length in nanometers

siniylev [52]

Answer:

4.57 × 10⁶ nanometers

Explanation:

In this problem we are asked to convert between two units i.e. a meter into nanometer. In sciences, the different units are used for a same quantity (achieved by multiplying conversion factors) to get rid of very small values and get a readable and intelligible values.

For Example:

In given statement the value of small distance is 4.5 × 10⁻³ meter the real number form of this number is 0.00457. Hence, this number can be converted to a very large number by multiplying it with 10⁹ or 1000000000. Hence,

4.5 × 10⁻³ × 1.0 × 10⁹ = 4.57 × 10⁶

Or,

4.5 × 10⁻³ meters = 4.57 × 10⁶ nanometers

Although the quantity is the same for same units but the number has changed.

4 0

3 years ago