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Liono4ka [1.6K]
3 years ago
11

Select the correct answer from each drop-down menu.

Chemistry
2 answers:
nataly862011 [7]3 years ago
8 0

The arrow shows that the bond between the chlorine atom and the fluorine atom is nonpolar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

Explanation:

  • The bond between Chlorine and fluorine is nonpolar bonding because both of them are sharing an equal number of electrons in the bond. H2, F2, and CL2 are common examples of this.
  • Chlorine and fluorine are electronegative molecules but Fluorine is above chlorine in the periodic table. Since fluorine is above Chlorine, fluorine has slightly highest electronegative nature compare to fluorine. This is the reason why Fluorine molecules are attracting electrons more than chlorine atoms. This making chlorine atoms slightly positive in Cl and F bonding.

Olin [163]3 years ago
5 0

Answer:

The arrow shows that the bond between the chlorine atom and the fluorine atom is polar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl.

The covalent bond between two atoms can be polar or nonpolar. This depends on the type of atoms that make it up: if the atoms are equal, the bond will be nonpolar (since no atom attracts electrons more strongly). But, if the atoms are different, the bond will be polarized towards the most electronegative atom, because it will be the atom that attracts the electron pair with more force. Then it will be polar.

So in this case, being two non-metallic elements, it is a covalent bond, and, following the definition previously presented, it is a polar bond, indicated by the arrow shown in the image.

The arrow also indicates that the atoms shared between both elements are more strongly attracted by F, due to the fact that it has a higher electronegativity. And since the electrons are negatively charged, fluorine will have a slightly negative charge, while chlorine will have a slightly positive charge.

So, finally, the arrow shows that the bond between the chlorine atom and the fluorine atom is polar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

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1. Calculate the RFM of Fe(NO3)2
miss Akunina [59]

Answer:

The Relative Formula Mass of Fe(NO₃)₂ is 179.8524 grams

Explanation:

The Relative Formula Mass is the mass of one mole of a compound expressed in grams, obtained by adding together the Relative Atomic Masses, RAM, of the elements which makes the compound

The Relative Formula Mass of a compound is the same as its Relative Molecular Mass

The relative formula mass of Fe(NO₃)₂ is given as follows;

The relative atomic mass of Fe = 55.845 amu

The relative atomic mass of nitrogen, N = 14.0067 amu

The relative atomic mass of oxygen, O = 15.999 amu

Therefore, we have;

The formula mass of Fe(NO₃)₂ = (55.845 + 2×(14.0067 + 3×15.999)) amu = 179.8524 amu

The Relative Formula Mass of Fe(NO₃)₂ = 179.8524 grams.

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3 years ago
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3 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
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