Question

The air in a balloon with a volume of 25.0 liters is heated from 20° C to 60° C. If the pressure stays the same, what will be the new volume of the balloon​

Answer 1

Answer:

New volume of the balloon will be 28.4 L.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                          $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

where $V_{1}$ and $V_{2}$ are volume of gas at $T_{1}$ and $T_{2}$ temperature (in kelvin scale) respectively.

Here $V_{1}=25.0L$, $T_{1}=(273+20)K=293K$ and $T_{2}=(273+60)K=333K$

So $V_{2}=\frac{V_{1}T_{2}}{T_{1}}=\frac{(25.0L)\times (333K)}{293K}$  = 28.4 L

So new volume of the balloon will be 28.4 L.