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Answer:
B.) 1.3 atm
Explanation:
To find the new pressure, you need to use Gay-Lussac's Law:
P₁ / T₁ = P₂ / T₂
In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.
P₁ = 1.2 atm P₂ = ? atm
T₁ = 20 °C + 273 = 293 K T₂ = 35 °C + 273 = 308 K
P₁ / T₁ = P₂ / T₂ <----- Gay-Lussac's Law
(1.2 atm) / (293 K) = P₂ / (308 K) <----- Insert values
0.0041 = P₂ / (308 K) <----- Simplify left side
1.3 = P₂ <----- Multiply both sides by 308
1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??
4.93 x ( 6.02x10²³) / 1 =
=> 2.96x10²⁴ atoms
Answer: X3+
Explanation:
Every atom aim to achieve stability by receiving electrons or giving their valence electrons in order to have a complete outermost shell of 2 (duplet) or 8 (octet structure).
In this case, the atom X will easily give off its three valence electrons to another atom(s), thereby forming a trivalent positive ion (X3+) with a stable duplet or octet structure (i.e an outermost shell with 2 or 8 electrons).
X --> X3+ + 3e-
Thus, due to the give away of three electrons (3e-), the atom X becomes X3+.
Answer:
It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M
Explanation:
A zero-order reaction follows the equation:
[A] = [A]₀ - kt
<em>Where [A] is actual reaction of the reactant = 0.100M</em>
<em>[A]₀ the initial concentration = 0.537M</em>
<em>k is rate constant = 0.075Ms⁻¹</em>
<em>And t is time it takes:</em>
<em />
0.100M = 0.537M -0.075Ms⁻¹t
-0.437M = -0.075Ms⁻¹t
5.83s = t
It takes 5.83s to decrease the concentration of the reactant from 0.537M to 0.100M
