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babunello [35]
3 years ago
14

Fluoride is moderately basic, by far the most basic of the halides. It is a terrible leaving group. Fluoride is many orders of m

agnitude better than bromide in leaving group ability. Bromide is many orders of magnitude better than fluoride in leaving group ability. Bromide ion is so weak it is not considered at all basic; it is an excellent leaving group.
Chemistry
1 answer:
TEA [102]3 years ago
3 0

Answer:   Bromide is many orders of magnitude better than fluoride in leaving group ability

Explanation:

As Size of an atom  Increases,  the Basicity Decreases this is because  if we move downwards  from the top of the periodic table to the bottom of the periodic table, the size of an atom increases. As size increases, basicity will decrease, meaning the element  will be less likely to act as a base implying that the element will be less likely to share its electrons.

in the same vein. With an increase in size, basicity decreases, making the ability of the leaving group to leave increase to increase . This can be seen in the halogens going down the group  from

F--- worst

Cl----fair

Br ----good

 I-----excellent

with fluorine having the worst ability to leave than Bromine which is better in terms of the leaving group ability.

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Please solve! Thanks
WARRIOR [948]

Answer:

Oxygen needed for Stannous Oxide: 1.350g

Oxygen needed for Stannic Oxide: 2.710g

Explanation:

You're working with 10.00 grams of Tin mass for both Stannous Oxide and Stannic Oxide.

- 10.00 grams of Tin for Stannous Oxide is already 88.10% of the mass needed. You need to find how much 11.90% of Oxygen mass is needed to create the compound. Find a factor that you can multiply 88.10% by to get 100%

- 88.10 * x = 100

- Solve for x and you get 1.135

- Multiply that number by the mass of Tin (10.00 grams) to get the complete compound (Mixture of Tin and Oxygen).

- 10.00g * 1.135 = 11.35g (Tin + Oxygen)

- Subtract (Compound - Tin) to find Oxygen

- 11.35g - 10.00g = 1.350g (Oxygen)

Repeat the process with Stannic Oxide

- Find the factor that gets 78.70% to 100%

- 100/78.70 = 1.271

- Multiply by Tin mass

- 10.00g * 1.271 = 12.71g (Compound)

- Subtract Compound by Tin

- 12.71g - 10.00g = 2.710g (Oxygen)

7 0
2 years ago
How much heat do you need to raise the temperature of 100g of aluminum from 30 C to 150 C
SVEN [57.7K]

Answer:

Q = 10.8 KJ

Explanation:

Given data:

Mass of Al= 100g

Initial temperature = 30°C

Final temperature = 150°C

Heat required = ?

Solution:

Specific heat of Al = 0.90 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30°C

ΔT = 120°C

Q = 100g×0.90 J/g.°C× 120°C

Q = 10800 J       (10800j×1KJ/1000 j)

Q = 10.8 KJ

4 0
3 years ago
Read 2 more answers
HELP! will mark brainliest if gotten right
Lorico [155]
The answer is B i think
5 0
3 years ago
During strenuous exercise, the NADH formed in the glyceraldehyde 3-phosphate dehydrogenase reaction in skeletal muscle must be r
vekshin1

Answer:

The answer is pyruvate → lactate

Explanation:

In the reaction of glycolysis, glucose breaks down to form pyruvate yielding ATP and NADH.

Under or during strenuous exercise, which is an anaerobic condition, lactate is formed by the reoxidization of NADH and the conversion of pyruvate to lactate.

6 0
3 years ago
When forming positive ions transition metals comply gain electrons??
AlekseyPX

Answer:

elements on the left-hand side of the periodic table such as sodium and magnesium prefer to lose electrons to form a cation because this requires less energy to obtain a stable octet, and vice-versa for the right-hand side of the periodic table e.g. fluorine. However, using this reasoning I am not sure why all transition metals tend to lose electrons rather than gain them.

7 0
3 years ago
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