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dem82 [27]
3 years ago
15

In 2005​, about 5 billion gal of renewable​ fuels, such as ethanol and other​ biofuels, were used in the United States. The ener

gy law passed in 2007 requires that 35 billion gal of such fuels be used by 2022. What is the percent of​ increase?
Mathematics
1 answer:
kolezko [41]3 years ago
8 0
11.11
 <span>5/45 = x/100 (reduce fraction to lowest terms to make it easier to work with) 
1/9 =x/100 
.1111 = x/100 
.1111x100 = x 
11.11 = x 
</span>
You might be interested in
With a ten dollar bill how much change do i get back if i buy four items, priced at 1.79, 2.99, 4.37 and 0.33
enot [183]

Add the price of the items bought and then subtract that from ten dollars:


Total bought:  1.79 + 2.99 + 4.37 + 0.33 = $9.48


Change back: 10.00 - 9.48 = 0.52


you would get $0.52 back in change.

5 0
3 years ago
Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput
Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0
3 years ago
19810 rounded to the nearest hundred
Cloud [144]
19,810 rounded to the nearest hundred is 19,800.
8 is in the hundreds place, and the number 1 is in front of it.
 
Numbers 1-4 in front of the number make the number stay the same.

Numbers 5-9 in front of the number make the numbers round up one number.
3 0
3 years ago
Read 2 more answers
QUICK WHAT IS:which expression represents a factorization of 32m + 56mp
Anna71 [15]
Simplifying that expression will be
32m + 56mp = 8m (4 + 7p)
5 0
3 years ago
NO LINKS!!!!
DedPeter [7]

9514 1404 393

Answer:

  3. vertical stretch by a factor of 2; shift right 1 and down 1

  4. shift left 4 and up 4 (no stretch or shrink)

Step-by-step explanation:

The vertex form equation is ...

  y = a(x -h)^2 +k

It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.

Compare the the given equations to the above form to see the transformations.

__

3. (a, h, k) = (2, 1, -1)   ⇒   vertical stretch by a factor of 2; shift right 1, down 1

4. (a, h, k) = (1, -4, 4)   ⇒   no vertical stretch; shift left 4, up 4

6 0
2 years ago
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