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mina [271]
3 years ago
7

Consider the following intermediate chemical equations. 2 equations. First: C(s)+(1/2)O2(g) ---->CO(g). Second: CO(g)+(1/2)O2

(g) ---->CO2(g). How will oxygen appear in the final chemical equation?
Chemistry
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

The oxygen will appear in the final stage if the oxygen is excess from the beginning.

Explanation:

1. C +(1/2)O2 —> CO

2. CO+(1/2)O2—> CO2

The first stage explains that the oxygen is limited and hence CO is produced.

The 2nd stage explains that if the oxygen is excess, then CO2 will be produced.

The overall reaction when oxygen is excess is given by:

C + O2 —> CO2

kogti [31]3 years ago
5 0

Answer:

A

Explanation:

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Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the
Olin [163]

Firstly we need to determine the partial pressure of O2:

\begin{gathered} P_{O_2}=X\times P_T \\ P_{O_2}:partial\text{ }pressure \\ X:mole\text{ }fraction \\ P_T:total\text{ }pressure \\  \\ P_{O_2}=0.209\times0.35\text{ }atm \\ P_{O_2}=0.073\text{ }atm \end{gathered}

We will now use the Henry's Law equation to determine the solubility of the gas:

\begin{gathered} c=K_H\times P_{O_2} \\ c:solubility\text{ }or\text{ }concentration\text{ }of\text{ }the\text{ }gas(M) \\ K_H:Henry^{\prime}sLawconstant=3.7\times10^{-2}M\text{ }atm^{-1} \\ P_{O_2}:partial\text{ }pressure\text{ }of\text{ }the\text{ }gas=0.073atm \\  \\ c=3.7\times10^{-2}M\text{ }atm^{-1}\times0.073 \\ c=2.7\times10^{-3}M \end{gathered}

Answer: Solubility is 2.7x10^-3 M

6 0
10 months ago
In the operation of the Heat Transfer Service Unit, one of the variables you can control is the rate of cooling water flowing ag
max2010maxim [7]

Answer:

A. The rate of heat transfer through the material would increase.

Explanation:

To calculate the heat transfer in a heat exchanger you decide that there is not heat leakage to the surroundings, that means that  magnitude of the two transfer rates will be equal. Any heat lost by the hot fluid, is gained by the cold fluid. The equation that describes this is Q = m×Cp×dT

Where:

heat = mass flow ×specific heat capacity × temperature difference

So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.

5 0
3 years ago
Read 2 more answers
20.352 mL of chlorine under a pressure of 680. mm Hg are
Lunna [17]

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

7 0
2 years ago
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How many orbitals are in the 5th energy level?
Alexandra [31]

Answer:7

Explanation:

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3 years ago
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I dont understand this question can u guys help
diamong [38]

Answer: B

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