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mina [271]
3 years ago
7

Consider the following intermediate chemical equations. 2 equations. First: C(s)+(1/2)O2(g) ---->CO(g). Second: CO(g)+(1/2)O2

(g) ---->CO2(g). How will oxygen appear in the final chemical equation?
Chemistry
2 answers:
-BARSIC- [3]3 years ago
8 0

Answer:

The oxygen will appear in the final stage if the oxygen is excess from the beginning.

Explanation:

1. C +(1/2)O2 —> CO

2. CO+(1/2)O2—> CO2

The first stage explains that the oxygen is limited and hence CO is produced.

The 2nd stage explains that if the oxygen is excess, then CO2 will be produced.

The overall reaction when oxygen is excess is given by:

C + O2 —> CO2

kogti [31]3 years ago
5 0

Answer:

A

Explanation:

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Nana76 [90]

Answer:

3H2SO4 + 2B(OH)3 -> B2(SO4)3 + 6H2O

Explanation:

3 0
4 years ago
4) A 4.00 L balloon is filled with 0.297 moles of helium gas with a pressure
Nadya [2.5K]

Answer: 149

Explanation:

Using the ideal gas equation; PV = nRT

P= Pressure = 0.910 atm,     T= Temperature = ?

V= Volume = 4.0L                  R = Gas constant = 0.08206 L.atm/mol/K

n = number of moles = 0.297

Making 'T' the subject of the formular, we have;

T = P V/ n R   =  0.910  x 4  /  0.297 x 0.08206

                       =  149

6 0
3 years ago
For which of the reactions listed below will Gibbs free energy always be
Vanyuwa [196]

Answer:

an exothermic reaction that Increase in entropy

3 0
3 years ago
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What is the correct balanced chemical equation for this reaction?
Lapatulllka [165]
B)
CH₄ + 2O₂ ---> CO₂ + 2H₂O
7 0
3 years ago
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Write the following numbers in ordinary notation.
adoni [48]

Answer:

Explanation:

The values are given in scientific notation.

Scientific notation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

Ordinary notation:

The ordinary notation is expended notation of writing the numerical values which is normal way. The numbers are written as they are, without the power of 10.

a) 7.356 ×10⁻⁶ km

0.000007356 km

b) 3.02 ×10⁻⁵ g

0.0000302 g

c) 8.348 ×10⁶ Kg

8,348,000 kg

d) 7.6352 ×10⁻³ s

0.0076352 s

4 0
3 years ago
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