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Sphinxa [80]
2 years ago
7

Please help. It's for chemistry

Chemistry
1 answer:
irinina [24]2 years ago
3 0
What do i help with what
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NEED HELP FAST!!!!!!!!!!!!
erma4kov [3.2K]
Covalent for the first one
8 0
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C2952H4664N812O832S8Fe4+NaC4H3O4SAu+Fe(SCN)2+Fe(NH4)2(SO4)2.6H2O+C4H8Cl2S+C8H12MgN2O8=C55H72MgN4+Na4Fe(CN)6+AuSC6H11O5+HClO4+H2S
Scorpion4ik [409]

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7 0
3 years ago
Methylene chloride (CH2Cl2) has fewer chlorine atoms than chloroform (CHCl3). Nevertheless, methylene chloride has a larger mole
icang [17]

Answer:

Explanation has been given below.

Explanation:

  • Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
  • Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
  • First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
  • Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
  • Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
  • Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.
3 0
3 years ago
A 1.250-g sample of benzoic acid, C7H6O2, was placed in a combustion bomb. The bomb was filled with an excess of oxygen at high
Degger [83]

Answer:

3224 kJ/mol

Explanation:

The combustion of benzoic acid occurs as follows:

C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE

The change in temperature in the reaction is the change due the energy released, that is:

3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts

To find the heat released per mole we have to find the moles of benzoic acid:

<em>Moles benzoic acid -Molar mass: 122.12g/mol-:</em>

1.250g * (1mol / 122.12g) = 0.0102 moles

<em />

The dE combustion per mole of benzoic acid is:

33.00kJ / 0.0102moles =

<em>3224 kJ/mol </em>

4 0
3 years ago
The length of a copper wire is 1.6 centimeters (cm). What is the length of this wire in meters (m)? 1.6 mc031-1.jpg 10–3 m 1.6 m
Klio2033 [76]
I believe the answer is  0.016. if i am wrong please tell me if it's wrong. the second option 
7 0
3 years ago
Read 2 more answers
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