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2 years ago

Which of these solids are most likely amorphous solids? Select all that apply. Rubber sugar plastic candle wax graphite glass.

Chemistry

2 answers:

raketka [301]2 years ago

5 0

Answer:

Rubber, plastic,candle wax, graphite glass

Explanation:

they all lack internal structure

Ostrovityanka [42]2 years ago

3 0

The solids are characterized as amorphous and crystalline solids based on the arrangement of atoms. The solids that are amorphous are rubber, plastic, candle wax, and glass.

<h3>What are amorphous solids?</h3>

The solids have the arrangement of atoms in the lattice. The solids with an appropriate arrangement of atoms are crystalline solids. For example, sugar, graphite.

The solids with irregular arrangements of atoms in the lattice are amorphous solids. For example, glass, rubber.

Thus, the solids that are amorphous in nature are rubber, plastic, candle wax, and glass.

Learn more about amorphous solids, here:

brainly.com/question/4626187

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bagirrra123 [75]

Answer:

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3 years ago

Which 2 resonance forms destablize the carbocation intermediate if bezonitrile undergoes chlronation at the ortho or para positi

Anna11 [10]

The question is incomplete, the complete question is shown in the image attached

Answer:

A and B

Explanation:

The electrophilic substitution of arenes yields a cation intermediate. The positive charge of the cation is delocalized over the entire ring.

The -CN group directs incoming electrophiles to the ortho/para position. The resonance structures for the chlorination of benzonitrile are shown in the question.

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8 0

3 years ago

Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.