Ask question

Ask question

All categories

2 years ago

12

A measure of the amount of light received on Earth is a star's ____. a. apparent magnitude c. position in space b. absolute magn

itude d. size

2 answers:

Neko [114]2 years ago

7 0

B. I hope this helps!!!

Nezavi [6.7K]2 years ago

3 0

B. I hope this helps!!!

You might be interested in

A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child conti

expeople1 [14]

Newton's first law of motion

3 0

2 years ago

Read 2 more answers

Does poop come out the pp or the butt please help im so confused best awnser gets brainleist

natulia [17]

Answer:

no poop comes out from your but

Explanation:

5 0

2 years ago

Read 2 more answers

How does the speed of visible light compare with the speed of gamma rays

DochEvi [55]

Answer:

They are the same

Explanation:

Electromagnetic waves consist of perpendicular oscillations of electric and magnetic field, which oscillate perpendicularly to the direction of motion of the wave (transverse wave). One property of the electromagnetic waves is that they travel in a vacuum always at the same speed, called speed of light:

$c=3.0\cdot 10^8 m/s$

Electromagnetic waves are classified into 7 different types according to their frequency; from highest to lowest frequency, we have:

Gamma rays

X-rays

Ultraviolet

Visible light

Infrared

Microwaves

Radio waves

We see that both visible light and gamma rays are electromagnetic waves, so they both travel in a vacuum at the same speed, the speed of light.

3 0

3 years ago

A pelican hunts fish in the water. As the pelican flies above the water’s surface, why must it aim for the fish in a slightly di

GarryVolchara [31]

Answer

A

Explanation

The light the fish absorbs is sunlight, the light reflecting is UV

5 0

3 years ago

A railroad car of mass 2.50 3 104 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railro

ipn [44]

Answer:2.5 m/s

37.5KJ

Explanation:

Let $u_1, u_2 , v_f$ be the initial velocity of rail road car ,coupled cars & Final velocity of system respectively.

$m=2.50\times 10^{4}$

Conserving momentum

$mu_1+3mu_2=4mv_f$

$4m+6m=4mv_f$

$v_f=2.5 m/s$

Therefore Final velocity of system is 2.5m/s

(b)Mechanical Energy lost =Initial Kinetic Energy -Final Kinetic Energy

$Initial Kinetic Energy=\frac{1}{2}m\left ( 4^2\right )+\frac{1}{2}m\left ( 2^2\right )=14m J$

$Final Kinetic Energy=\frac{1}{2}4m\left ( 2.5^2\right )=12.5m J$

$Mechanical Energy lost=14m-12.5m=3.75\times 10^4=37.5 KJ$

4 0

3 years ago