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Alika [10]
2 years ago
12

A measure of the amount of light received on Earth is a star's ____. a. apparent magnitude c. position in space b. absolute magn

itude d. size
Physics
2 answers:
Neko [114]2 years ago
7 0
B. I hope this helps!!!
Nezavi [6.7K]2 years ago
3 0
B. I hope this helps!!!
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A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child conti
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Newton's first law of motion
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Does poop come out the pp or the butt please help im so confused best awnser gets brainleist
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no poop comes out from your but

Explanation:

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How does the speed of visible light compare with the speed of gamma rays
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Answer:

They are the same

Explanation:

Electromagnetic waves consist of perpendicular oscillations of electric and magnetic field, which oscillate perpendicularly to the direction of motion of the wave (transverse wave). One property of the electromagnetic waves is that they travel in a vacuum always at the same speed, called speed of light:

c=3.0\cdot 10^8 m/s

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X-rays

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Visible light

Infrared

Microwaves

Radio waves

We see that both visible light and gamma rays are electromagnetic waves, so they both travel in a vacuum at the same speed, the speed of light.

3 0
3 years ago
A pelican hunts fish in the water. As the pelican flies above the water’s surface, why must it aim for the fish in a slightly di
GarryVolchara [31]

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A

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The light the fish absorbs is sunlight, the light reflecting is UV

5 0
3 years ago
A railroad car of mass 2.50 3 104 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railro
ipn [44]

Answer:2.5 m/s

37.5KJ

Explanation:

Let u_1, u_2 , v_f be the initial velocity of rail road car ,coupled cars & Final velocity of system respectively.

m=2.50\times 10^{4}

Conserving momentum

mu_1+3mu_2=4mv_f

4m+6m=4mv_f

v_f=2.5 m/s

Therefore Final velocity of system is 2.5m/s

(b)Mechanical Energy lost =Initial Kinetic Energy -Final Kinetic Energy

Initial Kinetic Energy=\frac{1}{2}m\left ( 4^2\right )+\frac{1}{2}m\left ( 2^2\right )=14m J

Final Kinetic Energy=\frac{1}{2}4m\left ( 2.5^2\right )=12.5m J

Mechanical Energy lost=14m-12.5m=3.75\times 10^4=37.5 KJ

4 0
3 years ago
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