1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vsevolod [243]
2 years ago
8

A sample of helium gas has a volume of 900. milliliters and a pressure of 2.50 atm at 298 K. What is the new pressure when the t

emperature is changed to 336 K and the volume is decreased to 450. milliliters?
Physics
1 answer:
Sladkaya [172]2 years ago
5 0

Answer:

<em>The new pressure = 5.64 atm.</em>

Explanation:

Using The general gas equation,

P₁V₁/T₁ = P₂V₂/T₂..................... Equation 1

making P₂ the subject of the equation

P₂ = P₁V₁T₂/V₂T₁ ...................... Equation 2

Where P₁ = initial pressure, V₁ = initial Volume, T₁ = Initial temperature, P₂ = final pressure, V₂ = final volume, T₂ = final Temperature.

<em>Given: P ₁= 2.5 atm, T₁ = 298 K, V₁= 900 milliliters, T ₂= 336 K, V₂ = 450 milliliters</em>

<em>Substituting these values into equation 2,</em>

<em>P₂ = (2.5×900×336)/(298×450)</em>

P₂ = 756000/134100

P₂ = 5.64 atm.

<em>Thus the new pressure = 5.64 atm.</em>

You might be interested in
A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from
Ulleksa [173]

Answer:

1270.64\ \text{J}

Explanation:

m = Mass of object = \dfrac{mg}{g}

mg = Weight of object = 20 N

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

\theta = Angle of slope = 30^{\circ}

f = Force of friction

fd = Work done against friction

The force balance of the system is

\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}

The work done against friction is 1270.64\ \text{J}.

8 0
3 years ago
A trombone can produce pitches ranging from 85 Hz to 660 Hz approximately. When the trombone is producing a 562 Hz tone, what is
tester [92]

To solve this problem we will apply the concept of wavelength, which warns that this is equivalent to the relationship between the speed of the air (in this case in through the air) and the frequency of that wave. The air is in standard conditions so we have the relation,

Frequency = f = 562Hz

Speed of sound in air = v = 331m/s

The definition of wavelength is,

\lambda = \frac{v}{f}

Here,

v = Velocity

f = Frequency

Replacing,

\lambda = \frac{331m/s}{562Hz}

\lambda = 0.589m

Therefore the wavelength of that tone in air at standard conditions is 0.589m

3 0
3 years ago
Two speakers, one directly behind the other, are each generating a 240-Hz sound wave. What is the smallest separation distance b
AveGali [126]

Answer:

The smallest separation distance between the speakers is 0.71 m.

Explanation:

Given that,

Two speakers, one directly behind the other, are each generating a 240-Hz sound wave, f = 240 Hz

Let the speed of sound is 343 m/s in air. The speed of sound is given by the formula as :

v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343\ m/s}{240\ Hz}\\\\\lambda=1.42\ m

To produce destructive interference at a listener standing in front of them,

d=\dfrac{\lambda}{2}\\\\d=\dfrac{1.42}{2}\\\\d=0.71\ m

So, the smallest separation distance between the speakers is 0.71 m. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
Acceleration is defined as the change in velocity divided by
mihalych1998 [28]

Answer:

change in time

Explanation:

8 0
3 years ago
1. The picture below shows Jamal pushing with a 100-Newton (N) force on a large box. Neither
r-ruslan [8.4K]

Answer:

100 newtons

Explanation:

Given,

Jamal pushing a large box by a force, F = 100 N

Work done on the large box is, W = 0

It is because the applied force is less than the force of the friction between the two surfaces.

Yet, there will be a force that is exerted by the large box on Jamal.

According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.

                                        F_{a} =-F_{r}

Hence, If the action force is 100 N, then the reaction force should be in 100 N

4 0
3 years ago
Read 2 more answers
Other questions:
  • A 4.0-n puck is traveling at 3.0 m/s. it strikes an 8.0-n puck, which is stationary. the two pucks stick together. their common
    8·1 answer
  • The impulse given to a ball with mass of 4 kg is 16 N s. If the ball starts from rest, what is its final velocity?
    13·1 answer
  • Which two conditions must exist in order for radiation to occur?
    13·1 answer
  • If you have lifted 10 pounds 2 feet, you have done ___ foot-pounds of work.
    11·1 answer
  • by scale drawing, find the resultant of vectors 70N inclined at100N and direction of the resultant 100N​
    6·1 answer
  • Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
    5·2 answers
  • AP physics here! Please help me answer only this question and then explain how you got your answer. After that, I will do the re
    7·1 answer
  • Please help!!!
    14·1 answer
  • As the frequency of a wave increases the wavelength.
    6·2 answers
  • The frequency of new cases of a disorder within a given time period is referred to as:______
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!