All categories

3 years ago

How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the

Physics

2 answers:

AnnyKZ [126]3 years ago

7 0

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

Delvig [45]3 years ago

5 0

Answer:39.2J

Explanation: I just answered this question and this was the correct answer. 4J is the wrong answer.

You might be interested in

Which planet is represented by the letter "h"?

Mandarinka [93]

The planet is represented as Saturn ♄

7 0

3 years ago

A 5kg box is being pulled for a force of 20 n and is sliding with an acceleration of 2 m/s. Find the coefficient of friction

RUDIKE [14]

Answer:

Coefficient of friction = 0.5

Explanation:

Given:

Mass of box = 5 kg

Force applied = 20 N

Acceleration = 2 m/s²

Find:

Coefficient of friction

Computation:

Friction force = Mass x Acceleration.

Friction force = 5 x 2

Friction force = 10 N

Coefficient of friction = Friction force / Force applied

Coefficient of friction = 10 / 20

Coefficient of friction = 0.5

3 0

2 years ago

A _________ is a graphical representation of association between variables.

tino4ka555 [31]

A. scatter plot (100% positive, btw quizzes is a good tool for answers)

3 0

3 years ago

Read 2 more answers

A wrecking ball is hanging at rest from a crane when suddenly the cable breaks. The time it takes for the ball to fall halfway t

Naddik [55]

Answer:

1.697s

Explanation:

We use the second equation of free fall under gravity as follows;

$h=ut+\frac{1}{2}gt^2...............(1)$

Since the ball fell freely, u = 0m/s, therefore equation (1) reduces to

$h=\frac{1}{2}gt^2...............(2)$

Given that h is the total height the ball falls through in time t seconds.

However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of $\frac{h}{2}$ in 1.2s. Hence we can write the following, given that $g=9.8m/s^2$ ;

$\frac{h}{2}=\frac{1}{2}*9.8*1.2^2\\hence\\h=9.8*1.2^2\\h=14.112m$

We can now proceed to find the time t for which it falls through h = 14.112m as follows;

$14.112=\frac{1}{2}*9.8*t^2\\14.112=4.9t^2\\t^2=\frac{14.112}{4.9}\\t^2=2.88\\t=\sqrt{2.88} \\t=1.697s$

8 0

3 years ago

As a simple pendulum swings back and forth, the forces acting on the suspended object are the force of gravity, the tension in t

My name is Ann [436]

Answer:

Tension: No, Force of Gravity and Air Resistance: Yes.

Explanation:

The air resistance and the correspondent component of the force of gravity will do work since both they are parallel/antiparallel to the direction of motion. Tension will not do work, since its perpendicular to the direction of motion.

8 0

3 years ago