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den301095 [7]
3 years ago
15

How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the

Physics
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

Delvig [45]3 years ago
5 0

Answer:39.2J

Explanation: I just answered this question and this was the correct answer. 4J is the wrong answer.

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3 years ago
When a 40V battery is connected across an unknown resistor there is a current of 100 ma  in the circuit.
amm1812

Answer:

R = 400 ohms.

Explanation: Voltage of the battery, V = 40 V. Current in the unknown resistor I = 100mA. Let R is the resistance of the resistor. It can be calculated using Ohm's law it gives the relationship between the voltage, resistance and current.. R = V/I. R = 40 V/10-¹A. R = 400 Ohm's. So, the value of the resistance of the resistor is 400 Ohm's

4 0
2 years ago
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A physics student throws a ball thrown horizontally from the top of a building with a speed of 8 m/s. The student measures the h
Alekssandra [29.7K]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete question in the attached file.

a_x = 0\\\\a_y = -g = -9.81\ \ \frac{m}{s^2} \\\\v_{iy} = 0 \\\\y = v_{iy} \times t+ \frac{1}{2ay} \times t^2 \\\\ 15 = \frac{1}{2} \times 9.8 \times t^2 \\\\t = \sqrt{(2 \times \frac{15}{9.8})} \\\\

  = 1.75 \ sec \\\\

Distance:

x = v_{ix} \times t \\\\

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Explanation:

If an object's speed (velocity) is increasing at a constant rate then we say it has uniform acceleration. The rate of acceleration is constant. If a car speeds up then slows down then speeds up it doesn't have uniform acceleration.

A body has a uniform acceleration if it travels in a straight line and its velocity increases by equal amount in equal intervals of time. For Ex:Motion of freely falling body, bicycle going down the slope, ball rolling down in inclined plane.

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3 years ago
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