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Marat540 [252]
3 years ago
14

5. A vitamin contains 1.5 x 10' grams of zinc. How many moles of zinc are in the vitamin?

Chemistry
1 answer:
Anni [7]3 years ago
7 0

Answer:

                      2.29 × 10⁻⁴ moles

Explanation:

Data Given:

                 Chemical Symbol of Zinc  =  Zn

                 Mass of Zinc   =  1.5 × 10⁻² g

                 A.Mass of Zinc  =  65.38 g.mol⁻¹

The Atomic Mass of Zinc can be obtained from periodic table. While, the mass is given in statement. Also, it is important to know the symbol because some elements exist in diatomic or polyatomic forms i.e. H₂, N₂, S₈ e.t.c.

                 Mole is the unit used to calculate the amount of substance. It has following general forms,

                                             Mole =  Mass / M.Mass

And,

                     Mole =  # of Particles / 6.022 × 10²³ particles.mol⁻¹

Hence, using first equation,

                     Moles  =  1.5 × 10⁻² g / 65.38 g.mol⁻¹

                     Moles =  2.29 × 10⁻⁴ moles

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6 0
3 years ago
Read 2 more answers
Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

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3 years ago
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
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Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

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