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RUDIKE [14]
2 years ago
9

A student sets up a box with a flashlight that shines on a mirror located at position X. Other possible locations for objects in

the box are labeled A-E.
How can the student place objects in the box to have all the light from the flashlight shine back on the flashlight?
Chemistry
2 answers:
pentagon [3]2 years ago
5 0

Answer:

If all the objects are placed at the same angle.

Explanation:

If all the objects are placed at the same angle so all the light from the flashlight shine comes back to the flashlight. If the A object is placed at the specific location at which the mirror X reflects the light after hitting it, then the other E object is placed at the location where the light comes after reflecting the A object then the light comes back to the flashlight if the angle between objects placement is right.

Evgesh-ka [11]2 years ago
3 0

Answer:

d

Explanation:

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If I have 12.0 volume of gas at pressure of 1.10 and temperature of 200k, what is the number of moles? (R=8314)
arsen [322]

Answer:

7.94 x 10^6 mol

Explanation:

PV=nRT

n=(PV)/(RT)

n=(1.10*12.0)/(8314*200)

n=7.94 x 10^6 mol

5 0
3 years ago
How much energy is released when 0.40 mol C6H6(g) completely reacts with oxygen?
Vsevolod [243]
 <span>This question asksyou to apply Hess's law. 
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C. 
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3 
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12 
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation. 
Then, 
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12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ 
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ 
______________________________________... 
2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ 
I hope this helps and my answer is right.</span>
4 0
3 years ago
Read 2 more answers
What additional tests would be needed to establish the exact position of hydrogen?
Gemiola [76]
The question above is incomplete, the full question is given below:
What additional test would be needed to establish the exact position of hydrogen in the activity series of the following elements: magnesium, zinc, lead, copper and silver.

ANSWER
The position of hydrogen on a reactivity series can be determined by its ability to displace oxygen from the oxide of the metal concerned. If hydrogen is more reactive than a metal, it will displace oxygen from the metal oxide and reduce the metal oxide to its metal. If the metal is more reactive than hydrogen, hydrogen will not be able to reduce the metal oxide to its metal.
5 0
3 years ago
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Mariana [72]
Not sure if this is what you mean but l= A/w
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4 0
3 years ago
Simplify: <br>(100 m)/(26 s)
podryga [215]

100m/26s=50m/13s

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4 0
3 years ago
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