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Maru [420]
2 years ago
11

1. An object is traveling at a constant velocity of 30 m/s when it experiences a constant

Physics
1 answer:
Yanka [14]2 years ago
7 0

Answer:use

Explanation:google

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The woman in the first photo lifts a plant 2 m
Serjik [45]

Answer:

65x2=130

that's what she does

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3 years ago
How long does it take for mars to rotate on its axis
Svetllana [295]

Hello There!

It takes the planet Mars around 24 hours, 37 minutes, 23 seconds to rotate on its axis. This is around the same amount of time that it takes our planet to rotate once on its axis.

8 0
3 years ago
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Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from
Akimi4 [234]

The change in the Gibb's free energy per mole (G) is 1.96 J.

The given parameters:

  • Density of the ice, ρ = 917 kg/m³
  • Initial pressure, P₁ = 1.0 bar
  • Final pressure, P₂ = 2.0 bar
  • Temperature, T = - 10 C
  • Mass of water = 18 g

The change in the Gibb's free energy per mole (G) is calculated as follows;

\Delta G = V(P_2-P_1) \\\\

where;

V is the volume of the ice

Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L

Change in pressure;

P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm

The change in the Gibb's free energy per mole (G);

\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G =  0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.

Learn more about Gibb's free energy here: brainly.com/question/10012881

3 0
2 years ago
Can someone help please I’ll mark brainless
morpeh [17]

Answer:

Synthesis Reaction

Explanation:

6 0
2 years ago
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Calcular la energía cinética de un Coyote de 30 kg que corre tras su presa con una velocidad de 65 km/h
Mumz [18]

Respuesta:

4.9 × 10³ J

Explicación:

Paso 1: Información provista

  • Masa del coyote (m): 30 kg
  • Velocidad del coyote (v): 65 km/h

Paso 2: Convertir la velocidad del coyote de km/h a m/s

Vamos a usar los siguientes factores de conversion:

  • 1 km = 1000 m
  • 1 h = 3600 s

65 km/h × (1000 m/1 km) × (1 h/3600 s) = 18 m/s

Paso 3: Calcular la energía cinética del coyote (K)

Usarémos la siguiente fórmula.

K = 1/2 × m × v²

K = 1/2 × 30 kg × (18 m/s)² = 4.9 × 10³ J

6 0
3 years ago
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