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3 years ago

Calculate the potential energy of 5kg object sitting on a 3m ledge.

Physics

1 answer:

larisa [96]3 years ago

3 0

Potential Energy (Ep)= mass*force of gravity*height

Ep= (5kg)(-9.81m/s^2)(3m)
Ep= -147.15 J

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Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced

SpyIntel [72]

Answer: $0.0686 m^3$

Explanation:

Given

No of moles=2

$T=25^{\circ}\approx 298 K$

$P_1=210 KPa$

$T_2=48 ^{\circ}\approx 321 k$

$P_2=77.7 KPa$

PV=nRT

Substitute

$77.7\times V_2=2\times 8.314\times 321$

$V_2=0.0686 m^3$

4 0

3 years ago

A spacecraft travels at 1.5 X 108 m/s relative to Earth. A process onboard the

kvasek [131]

Answer:

73.6 minutes

Explanation:

relative time = time interval / √(1 - observer velocity² / speed of light²)

we have relative time. we want time interval.

rearrange

time interval = relative time x √(1 - observer velocity² / speed of light²)

convert 85 mins into seconds

85 x 60 = 5100

1.5 x 10⁸ as a number is 150000000

for c = 299 792 458

time interval = 5100 x √(1 - 150 000 000² / 299 792 458²)

for c = 3 x 10⁸

time interval = 5100 x √(1 - 150 000 000² / 300 000 000²)

time interval = 5100 x 0.866

time interval = 4415.71

divide by 60 for back into minutes

time = 73.6 minutes

4 0

2 years ago

The amount of work done by two boys who apply 200 N of force in an

Aleksandr [31]

The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.

Answer: Option B

<u>Explanation: </u>

Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.

$\text { Work done }=\text { Force } \times \text { displacement }$

So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be

$\text { Work done }=200 \mathrm{N} \times 0=0$