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Readme [11.4K]
3 years ago
8

Calculate the potential energy of 5kg object sitting on a 3m ledge.

Physics
1 answer:
larisa [96]3 years ago
3 0
Potential Energy (Ep)= mass*force of gravity*height

Ep= (5kg)(-9.81m/s^2)(3m)
Ep= -147.15 J
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3 years ago
A 0.l ‑kilogram block is attached to an initially unstretched spring of force constant k = 40 N/m as shown right. The block is d
GalinKa [24]

Answer:

The maximum potential energy of the system is 0.2 J

Explanation:

Hi there!

When the spring is stretched, it acquires potential energy. When released, the potential energy is converted into kinetic energy. If there is no friction nor any dissipative forces, all the potential energy will be converted into kinetic energy according to the energy conservation theorem.

The equation of elastic potential energy (EPE) is the following:

EPE = 1/2 · k · x²

Where:

k = spring constant.

x = stretching distance.

The elastic potential energy is maximum when the block has no kinetic energy, just before releasing it.

Then:

EPE = 1/2 · 40 N/m · (0.1 m)²

EPE = 0.2 J

The maximum potential energy of the system is 0.2 J

8 0
3 years ago
Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each
jarptica [38.1K]

Answer with Explanation:

We are given that

I_1=29 A

I_2=78 A

d=38 cm=\frac{38}{100}=0.38 m

1 m=100 cm

a.Length of segment,l=20 m

Magnetic force ,F=\frac{2\mu_0I_1I_2 l}{4\pi d}

\frac{\mu_0}{4\pi}=10^{-7}

Substitute the values

F=\frac{10^{-7}\times 29\times 78\times 20}{0.38}=0.0119 N

Hence, the magnetic force exert by each segment on the other=0.0119 N

b.We know that when current carrying in the wires are in same direction then the force will attract to each other.

Hence, the force will be attractive.

4 0
3 years ago
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