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Readme [11.4K]
3 years ago
8

Calculate the potential energy of 5kg object sitting on a 3m ledge.

Physics
1 answer:
larisa [96]3 years ago
3 0
Potential Energy (Ep)= mass*force of gravity*height

Ep= (5kg)(-9.81m/s^2)(3m)
Ep= -147.15 J
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The boom of a fire truck raises a fireman (and his equipment – total weight 280 lbs) 60 ft into the air to fight a building fire
Simora [160]

Explanation:

Given that,

Weight = 280 lbs

Height = 60 ft

Power = 3.50 hp

(a). We need to calculate the work done by the boom on the fireman

Using formula of work done

Work\ done =Weight\ \times height

W'=W\times h

Put the value into the formula

W'=280\times60

W'= 16800 ftlbf

W'=\dfrac{16800}{778.169}

W'=21.59\ Btu

The work done by the boom is 21.59 Btu.

(b). We know that,

1 hp = 550 ft lbf

So, P = 3.50\times550

P=1925\ ft-lbf/s

We need to calculate the time

Using formula of time

t = \dfrac{W}{P}

Put the value into the formula

t=\dfrac{16800}{1925}

t =8.7\ sec

The time is 8.7 sec.

Hence, This is the required solution.

6 0
3 years ago
The image shows a wheel that’s wound up and released. The wheel moves up and down as shown. Identify the position of the wheel w
slega [8]

The highest point of the wheel is the position of the wheel when its potential energy is greatest.

<h3>At what position of the wheel potential energy is greatest?</h3>

The position of the wheel when its potential energy is greatest when it is at the highest point because potential energy depends on the height of an object. If the object is at more height then it has more potential energy and vice versa.

So we can conclude that the highest point of the wheel is the position of the wheel when its potential energy is greatest.

Learn more about energy here: brainly.com/question/13881533

#SPJ1

8 0
2 years ago
What is the acceleration of an object with a mass of
aev [14]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                             F = Force = 183 N

                                            m = Mass = 367 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\boxed{a=183 \ N / 367\ kg}

⇒ Resolving

\boxed{ a = 0.49 \ m/s^{2}}

Result:

The aceleration is <u>0,49 meters per second squared (m/s²)</u>

Good Luck!!

3 0
3 years ago
There is up to 30 times more gold in a tons of old mobile phones than in a tons of gold ore. true or false
FrozenT [24]

Answer:

true

Explanation:

dbgkdodocofkci ifkdcl k kfododocp v

3 0
2 years ago
I will mark brainliest! :D<br> SO please help me M8
Kobotan [32]

Answer: 100 J

Explanation: 1/2 5 x 2^2 = 100

Hope this made any sense.

7 0
3 years ago
Read 2 more answers
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