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Misha Larkins [42]
3 years ago
15

If you ride your bike at an average speed of 4 km/h and need to travel a total distance of 28 km,how long will it take you to re

ach your destination
Physics
2 answers:
Degger [83]3 years ago
8 0
<span>distance = rate * time 
d = 28 km 
r = 4 km/h 

Find t in hours. 
28km = 4km/h * t 
28km/4km/h = t 
7 hours = t 
t = 7</span>
s2008m [1.1K]3 years ago
7 0
We will use distance = rate * time formula.

Plug in the value: d = 28 km, r = 4 km / h

28 km = 4 km / h * t

Divide both sides by 4 km /h

28 km = 4 km / h * t = 7 h

So, it would take you 7 hours to reach your destination.
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IP A spark plug in a car has electrodes separated by a gap of 6.5×10−2 in . To create a spark and ignite the air-fuel mixture in
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Answer:

a.) V=5283.2 \ V

b.) V=4064\ V

Explanation:

<u>Electric Field and Potential Difference</u>

There are several conditions that must be met for a spark to be created into an air gap. Once the physical conditions are fixed, a minimum electric field is necessary for the spark to be initiated. Let s be the separation between the electrodes and V their potential difference. The electric field is

a.)

\displaystyle E=\frac{V}{s}

Solving for V

V=E.s

The separation is

s= 5.5\cdot 10^{-2}\ in=0.001651 \ m

Thus the potential difference is

V=3.2\cdot 10^{6}\ V/m\times 0.001651 \ m

V=5283.2 \ V

b.) If the separation was greater, the applied voltage needs to be greater if the electric field has to be constant. One possible measure to keep electrodes as close as possible is to build them as sharp edges. It gives the spark an easier path to travel to.

If the separation is 0.05 inches =0.00127 m

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3 years ago
A helicopter lifts a 81 kg astronaut 19 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
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Answer:

a) The work done on the astronaut by the force from the helicopter is W_{h}=16087.68\ J.

b) The work done on the astronaut by the gravitational force is  W_{g}=-15082.2\ J .

Explanation:

We are told that the mass of the astronaut is m=81\ kg, the displacement is \Delta x=19\ m, the acceleration of the astronaut is  |\vec{a}|=\frac{g}{15}  and the acceleration of gravity is g=9.8\ \frac{m}{s^{2}} .

We suppose that in the vertical direction the force from the helicopter F_{h} is upwards and the gravitational force F_{g} is downwards. From the sum of forces we can get the value of F_{h}:

                                               F_{h}-F_{g}=m.a

                                              F_{h}-mg=m.\frac{g}{15}

                                              F_{h}=mg(1+\frac{1}{15})

                              F_{h}=(\frac{16}{15}).81\ kg.\ 9.8\ \frac{m}{s^{2}}\ \Longrightarrow\ F_{h}=846.72\ N

We define work as the product of the force, the displacement of the body and the cosine of the angle \theta between the direction of the force and the displacement of the body:

                                                 W=F.\Delta x.\ cos(\theta)

a) The work done on the astronaut by the force from the helicopter

                                                  W_{h}=F_{h}.\Delta x

                                             W_{h}=846.72\ N.\ 19\ m

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b) The work done on the astronaut by the gravitational force

                                                   W_{g}=-F_{g}.\Delta x

                                                    W_{g}=-mg\Delta x

                                            W_{g}=-81\ kg.\ 9.8\ \frac{m}{s^{2}}.\ 19\ m

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