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Ostrovityanka [42]
3 years ago
14

Lidia plans an experimental investigation to see how the thickness of a lens affects the point where a beam of light is focused.

She plans to shine light through a lens and measure the distance to a screen that is placed where the beam focuses.What are the controls in Lidia’s investigation?
Physics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

The type of light and the material of lenz.

Explanation:

1) As the investigation is based on how the thickness of a lens effect the other variable. Thickness of the lenz is independent variable. So Lidia has to experiment with the different thicknesses in order to find the effect on dependent variable.

2) As the investigation is based to find the point where the beam of light is focused. It's a dependent variable and Lidia has no control over it. So the only thing she can do is to measure and observe how it respond to the changes in independent variable.

3) For conclusion, she has to make sure that the other variables are not effecting the output or results that is the beam point where the light is focused. So she must have to kept constant the type of light and material of lenz otherwise she won't be able to discriminate the effect of thickness of lenz from other causes.

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What mass has a rest energy of 100J?
alexandr1967 [171]

Answer:

option a is correct

Explanation:

<h2>I hope it's help you ❣️❣️</h2>
6 0
3 years ago
The pressure drop needed to force water through a horizontal 1-in diameter pipe if 0.60 psi for every 12-ft length of pipe. Dete
oksian1 [2.3K]

Answer:

The shear stress at a distance 0.3-in away from the pipe wall is 0.06012lb/ft²

The shear stress at a distance 0.5-in away from the pipe wall is 0

Explanation:

Given;

pressure drop per unit length of pipe = 0.6 psi/ft

length of the pipe = 12 feet

diameter of the pipe = 1 -in

Pressure drop per unit length in a circular pipe is given as;

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\

make shear stress (τ) the subject of the formula

\frac{\delta P}{L} = \frac{2 \tau}{r} \\\\\tau = \frac{\delta P *r}{2L}

Where;

τ is the shear stress on the pipe wall.

ΔP is the pressure drop

L is the length of the pipe

r is the distance from the pipe wall

Part (a) shear stress at a distance of  0.3-in away from the pipe wall

Radius of the pipe = 0.5 -in

r = 0.5 - 0.3 = 0.2-in = 0.0167 ft

ΔP = 0.6 psi/ft

ΔP, in lb/ft² = 0.6 x 144 = 86.4 lb/ft²

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0.0167}{2*12} =0.06012 \ lb/ft^2

Part (b) shear stress at a distance of  0.5-in away from the pipe wall

r = 0.5 - 0.5 = 0

\tau = \frac{\delta P *r}{2L}  = \frac{86.4 *0}{2*12} =0

3 0
3 years ago
A wave with a frequency of 80 Hz travels through rubber with a wavelength of 7.0 m. What is the velocity of the wave?
Scorpion4ik [409]

Answer:

560 m/s

Explanation:

Given,

Frequency ( f ) = 80 hz

Wavelength ( λ ) = 7.0 m = 7m

To find : Velocity ( v )

Formula : -

v = f λ

v = 80 x 7

v = 560 m/s

Hence, the velocity of the wave is 560 m/s.

5 0
2 years ago
A baseball goes from zero to 39 m/s in 0.917s. what is its average acceleration?
Ket [755]
(39 m/s / 917) x 1000 = 42.5m/s
5 0
3 years ago
A baseball is thrown at a 28° angle and an initial velocity of 70 m/s. Assume no air resistance. How far did the ball travel hor
Genrish500 [490]

Answer:

414.9 m

Explanation:

First, become familiar with the horizontal, and vertical vector components.

Vertical vector: Vy = V × sin (θ).

Horizontal vector: Vx = V × cos(θ).

Distance traveled = Velocity vector × time in the air.

Time in the air given Vy = 2 × Vy / g (in respect to the metric of the vector).

Range of the projectile = Vx² / g

Time in the air given Vx = (Vx + √(Vx)² + 2gh) / g.

Given a 28° angle with an initial velocity of 70m/s, we have enough information to calculate!

Vx = 70 m/s × cos(28°) ≈ 61.806 m/s

Vy = 70 m/s × sin(28°) ≈ 32.863 m/s

t = 2 × Vy / g

t = 2 × ≈32.863 / 9.8

t = ≈65.726 / 9.8

t ≈ 6.7 s

Distance traveled (horizontal) = Vx × t = 61.806 × 6.7 ≈ 414.9 m

6 0
2 years ago
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