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Maru [420]
2 years ago
14

A sports car accelerates from rest for 5 seconds reaching a velocity of 23.0 m/s.

Physics
1 answer:
denis-greek [22]2 years ago
4 0

Answer:

<h2>4.6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

<h3>a =  \frac{v - u}{t}  \\</h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

Since the body is from rest u = 0

From the question we have

a =  \frac{23 - 0}{5}  =  \frac{23}{5}  \\

We have the final answer as

<h3>4.6 m/s²</h3>

Hope this helps you

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<span>The four stages of listening include hearing, understanding, "Evaluating" and responding.

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5 0
3 years ago
What is the density of a block of marble that occupies 236 cm3 and has a mass of 824 g? answer in units of g/cm3 ?
REY [17]
Since the formula is mass/volume the density is 3.4915......g/cm^3
4 0
4 years ago
What is the equivalent resistance of the
BigorU [14]

Answer:

Approximately 111\; {\rm \Omega}.

Explanation:

It is given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega} are connected in a circuit in parallel.

Assume that this circuit is powered with a direct current power supply of voltage V.

Since R_{1} and R_{2} are connected in parallel, the voltage across the two resistors would both be V. Thus, the current going through the two resistors would be (V / R_{1}) and (V / R_{2}), respectively.

Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor: I = (V / R_{1}) + (V / R_{2}).

In other words, if the voltage across this circuit is V, the total current in this circuit would be I = (V / R_{1}) + (V / R_{2}). The (equivalent) resistance R of this circuit would be:

\begin{aligned} R &= \frac{V}{I} \\ &= \frac{V}{(V / R_{1}) + (V / R_{2})} \\ &= \frac{1}{(1/R_{1}) + (1 / R_{2})}\end{aligned}.

Given that R_{1} = 200\; {\Omega} and R_{2} = 250\; {\Omega}:

\begin{aligned} R &= \frac{1}{(1/R_{1}) + (1 / R_{2})} \\ &= \frac{1}{(1/(200\: {\rm \Omega})) + (1/(250\; {\rm \Omega}))} \\ &\approx 111\; {\rm \Omega}\end{aligned}.

7 0
2 years ago
A proton with a speed of 3.2 x 106 m/s is shot into a region between two plates that are separated by a distance of 0.23 m. As t
harina [27]

Answer:

<h2>The magnitude of the magnetic is 0.145 T</h2>

Explanation:

Given :

Speed of proton v = 3.2 \times 10^{6}\frac{m}{s}

Mass of proton m = 1.67 \times 10^{-27} Kg

The force on the proton in magnetic field is given by,

  F = q (v \times B)

  F = qvB \sin \theta

But \sin 90 = 1    (∵ Force is perpendicular to the velocity so \theta = 90)

  F = qvB

When particle enter in magnetic field at the angle of 90° so particle moves in circle

So force is given by,

  F = \frac{mv^{2} }{r}

Where r = radius but in our case 0.23 m, q = 1.6 \times 10^{-19} C

By comparing above two equation,

  B = \frac{mv}{qr}

  B = \frac{1.67 \times 10^{-27} \times 3.2 \times 10^{6}  }{1.6 \times 10^{-19} \times 0.23 }

  B = 0.145 T

5 0
3 years ago
A rocket explodes as it begins to launch. As a result, the rocket is destroyed
Alekssandra [29.7K]

Answer:

probably B

Explanation:

it's not their job to sort out the cost of cleaning it up or worry about the public opinion. they should only make sure it doesn't happen again so they should find out why it happened

7 0
3 years ago
Read 2 more answers
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