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erastovalidia [21]
3 years ago
6

Which of the following is a precipitation reaction?

Chemistry
1 answer:
erik [133]3 years ago
3 0

Answer:

The precipitated are option a and d.

Explanation:

2 LiI(aq) +Hg2(NO3)2(aq)  →  Hg2I2(s) ↓ + 2 LiNO3(aq)

Cation Hg2+ 2 in the presence of iodide,  a precipitated  is formed.

Zn(s) + 2AgNO3(aq) → 2 Ag(s) ↓ +Zn(NO3)2(aq)

Zinc starts to get rid, and some white particles also stick to it. Afterwards the solution becomes cloudy and a precipitate appears, which is the solid silver

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Molar concentration is

C=\frac{\eta}{V}

[V]=Liters

[\eta]=mol

\eta=C*V

V=25~mL=0.025~L

\eta=1.5*0.025

\boxed{\boxed{\eta=0.0375~moles}}
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You have 25.0 mL HCI of unknown concentration. It takes 12.5 of 0.2 M NaOH to neutralize the acid. Determine the concentration o
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The balanced equation for the reaction between NaOH and HCl is 
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
during neutralisation, number of H⁺ ions = OH⁻ ions. Together they form water molecules and neutralise the solution as water is neutral.
Number of NaOH moles in 1000 ml - 0.2 mol
therefore in 12.5 ml -0.2/1000 x 12.5
                                = 0.0025 mol
at neutralisation point , number of OH⁻ mol = number of H⁺ ions
    since stoichiometry of base to acid is 1:1
number of HCl moles reacted = 0.0025 mol
concentration is the number of moles in 1000 ml
in 25 ml number of HCl moles - 0.0025 mol
Therefore in 1000 ml - 0.0025 mol /25 x 1000
  concentration of HCl - 0.1 M
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