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nikitadnepr [17]
2 years ago
11

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days?

Chemistry
1 answer:
const2013 [10]2 years ago
4 0
If a person burns 2171 Cal each day, then in 2 days she will burn a total of 4242 calories which would be equivalent to 9083.464 kilojoules of energy. Hope this answers the question. Have a nice day. Feel free to ask more questions.
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Read “The Ozone Hole” and answer the question below. Write a short evaluation of the article’s reliability and scientific worth.
pantera1 [17]

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The ozone opening is to a greater degree a downturn, less a gap in the windshield. The ozone doesn't vanish through the layer, nor is there a uniform diminishing of the ozone layer. Also, it was found in 1913 by the French physicists Charles Fabry and Henri Buisson.  

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6 0
3 years ago
Read 2 more answers
Which best describes the particles in a gas when the temperature rises from 23 °C to 46 °C?
mariarad [96]
I think the correct answer is b. Temperature is proportional to the average kinetic energy so when temperarure rises so will the average kinetic energy. I hope this helps. Let me know if anything is unclear.
5 0
3 years ago
Please help fast, I will give brainliest.
frez [133]

Answer:

The reaction is favorable at all temperatures

Explanation:

Since G = H - TS, -H and +S would result in G = -H -TS, which will always be negative.

7 0
2 years ago
Which pair shares the same empirical formula?
ZanzabumX [31]

Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

4 0
3 years ago
Read 2 more answers
How many atoms of hydrogen are present: 2(NaHCO3)
Firlakuza [10]

Answer:

《HOPE IT WILL HELP YOU 》

Explanation:

2 Atom of Hydrogen are present in 2 (NaHCO3)

5 0
2 years ago
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