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nikitadnepr [17]
2 years ago
11

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days?

Chemistry
1 answer:
const2013 [10]2 years ago
4 0
If a person burns 2171 Cal each day, then in 2 days she will burn a total of 4242 calories which would be equivalent to 9083.464 kilojoules of energy. Hope this answers the question. Have a nice day. Feel free to ask more questions.
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In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
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5 0
2 years ago
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HELP!!!
vladimir2022 [97]

Answer:

2.5 × 10⁻⁵ M H₃O⁺ and 4.0 × 10⁻¹⁰ M OH⁻.

Explanation:

<em>∵ pH = - log[H₃O⁺]</em>

∴ 4.6 = - log[H₃O⁺].

∴ log[H₃O⁺] = - 4.6.

∴ [H₃O⁺] = 2.51 x 10⁻⁵.

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[H₃O⁺] = 2.51  x 10⁻⁵ M.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(2.51  x 10⁻⁵ M) = 3.98 × 10⁻¹⁰ M ≅ 4.0 × 10⁻¹⁰ M.

<em>So, the right choice is: 2.5 × 10⁻⁵ M H₃O⁺ and 4.0 × 10⁻¹⁰ M OH⁻.</em>

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3 years ago
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Why might nuclear fusion be a better source of energy on earth than nuclear fission?
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